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Elenna [48]
3 years ago
8

What is the term for the force exerted on an object by another object?

Physics
1 answer:
marshall27 [118]3 years ago
7 0

A: action force ... to which there is a reaction force

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Cars A and B have the same mass, but Car A's speed is 15 mph, whereas Car B is moving at 60 mph. The kinetic energy
kupik [55]

Answer:

16 times that of car A

Explanation:

Moving objects have kinetic energy which is calculated using the formula:

E=(1/2)mv² where m is the mass of the object and v is its velocity.

For car A, kinetic energy =1/2×m×15²

=112.5m........................................i

For car B,  the kinetic energy =1/2×m×60²

=1800m......................................ii

dividing ii by i we get

1800m/112.5m= 16.07

Therefore The kinetic energy of car B is 16.07 times that of car A

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3 years ago
Please Help Quick ASAP Hurry This is Physical Science
krok68 [10]

Answer:

Think it is C

Explanation:

Not sure!!!

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3 years ago
Which of the following correctly shows the chain of energy transfers that create surface currents on the ocean?
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D.
Solar energy is converted to wind energy which then drive surface currents.
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Galileo started modern science because he started using ? Rather than speculation
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By using the telescope
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A pendulum is made by letting a 4 kg mass swing at the end of a string that has a length of 1.5 meter. The maximum angle that th
olga nikolaevna [1]

Answer:

Approximately 7.8\; \rm J.

Explanation:

The change in the gravitational potential energy of the pendulum is directly related to the change in its height.

Refer to the sketch attached. The pendulum is initially at \rm P_2. Its highest point is at P_1. The length of segment \rm BP_2 gives the change in its height.

The lengths of \rm AP_1 and \rm AP_2 are simply the length of the string, 1.5\; \rm m. To find the length of \rm BP_2, start by calculating the length of \rm AB.

\rm AB forms a leg in the right triangle \rm \triangle AP_1B. Besides, it is adjacent to the 30^\circ angle \rm P_1\hat{A}B. Its length would be:

\rm AB = 1.5 \times \cos(30^\circ) \approx 1.30\; \rm m.

The length of \rm BP_2 would thus be

\rm BP_2 = AP_2 - AB = 1.5 - 1.30 \approx 0.20\; \rm m.

The change in gravitational potential energy can be found with the equation

\Delta \mathrm{GPE} = m \cdot g \cdot \Delta h. In this equation,

  • m is the mass of the object,
  • g \approx 9.81\; \rm N \cdot kg^{-1} near the surface of the earth, and
  • \Delta h is the change in the object's height.

In this case, m = 4\; \rm kg and \Delta h \approx 0.20\; \rm m. Therefore:

\Delta \mathrm{GPE} = 4 \times 9.81 \times 0.20 \approx 7.8\; \rm J.

6 0
3 years ago
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