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lukranit [14]
1 year ago
6

Given a circuit consisting of a DC battery of voltage 200 volts connected to a single resistor. If the electric current through

the resistor is 50000 mA then which of these is the resistance of the resistor in SI units?A)16B)24C)20D)4E)12
Physics
1 answer:
sertanlavr [38]1 year ago
7 0

Given:

The battery voltage, V=200 V

The current through the resistor, I=50000 mA=50000×10⁻³ A

To find:

The resistance of the resistor.

Explanation:

From Ohm's law, the voltage across a circuit is directly proportional to the current through the circuit.

Thus the voltage across the resistor is given by,

V=IR

On substituting the known values in the above equation,

\begin{gathered} 200=50000\times10^{-3}\times R \\ \Rightarrow R=\frac{200}{50000\times10^{-3}} \\ =4\text{ }\Omega \end{gathered}

Final answer:

The resistance of the resistor is 4 Ω

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An Olympic track runner starts from rest and has an acceleration of 2.4 m/s2 for 3.6 s, then has zero acceleration for the remai
rjkz [21]

Answer:

The runner's speed at the following times would remain 8.64 m/s.

Explanation:

Acceleration definition: Acceleration is rate of change in velocity of an object with respect to time.

In this case, after 3.6 seconds the acceleration is zero, it means that the velocity of the runner after 3.6 seconds is not changing and it will remain constant for the remainder of the race. Now, we have to find the velocity of the runner that he had after 3.6 seconds and that would be the runner's speed for the remainder of the race. For this we use first equation of motion.

First equation of motion:        Vf = Vi + a×t

Vf stands for final velocity

Vi stands for initial velocity

a stands for acceleration

t stands for time

In the question, it is mentioned that the runner starts from rest so its initial velocity (Vi) will be 0 m/s.

The acceleration (a) is given as 2.4 m/s²

The time (t) is given as 3.6 s

Now put the values of Vi, a and t in first equation of motion

                       Vf = Vi + a×t

                       Vf = 0 + 2.4×3.6

                       Vf = 2.4×3.6

                       Vf = 8.64 m/s

So,the runner's speed at the following times would remain 8.64 m/s.

5 0
3 years ago
What happens if you move a magnet near a could of wire
noname [10]

Answer:

The wire would stick to the magnet????????????????????????

Explanation:

3 0
3 years ago
What is the current in a series circuit with a resistance of 30 ohms and a potential difference of 120 volts?
mars1129 [50]
0.25A....................
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A brick is resting on a smooth wooden board that is at a 30° angle. What is one way to overcome the static friction that is hold
lubasha [3.4K]

Answer:

to overcome the out of friction we must increase the angle of the plane

Explanation:

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X axis

       fr - Wₓ = m    a                      (1)

Y axis  

       N- W_{y} = 0

       N = W_{y}

let's use trigonometry to find the components of the weight

        sin θ = Wₓ / W

        cos θ = W_{y} / W

        Wₓ = W sin θ

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the friction force has the formula

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from equation 1

at the point where the force equals the maximum friction force

in this case the block is still still so a = 0

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We can see that the quantities in parentheses with constants, so as the angle increases, the applied force must be less.

This is the force that balances the friction force, any force slightly greater than F initiates the movement.

Consequently, to overcome the out of friction we must increase the angle of the plane

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3 years ago
The alpha line in the balmer series of the hydrogen spectrum consists of light having a wavelength of 6.56. calculate the freque
guajiro [1.7K]
The alpha line in the Balmer series is the transition from n=3 to n=2 and with the wavelength of λ=656 nm = 6.56*10^-7 m. To get the frequency we need the formula: v=λ*f where v is the speed of light, λ is the wavelength and f is the frequency, or c=λ*f. c=3*10^8 m/s. To get the frequency: f=c/λ. Now we input the numbers: f=(3*10^8)/(6.56*10^-7)=4.57*10^14 Hz. So the frequency of the light from alpha line is f= 4.57*10^14 Hz. 
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