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lukranit [14]
1 year ago
6

Given a circuit consisting of a DC battery of voltage 200 volts connected to a single resistor. If the electric current through

the resistor is 50000 mA then which of these is the resistance of the resistor in SI units?A)16B)24C)20D)4E)12
Physics
1 answer:
sertanlavr [38]1 year ago
7 0

Given:

The battery voltage, V=200 V

The current through the resistor, I=50000 mA=50000×10⁻³ A

To find:

The resistance of the resistor.

Explanation:

From Ohm's law, the voltage across a circuit is directly proportional to the current through the circuit.

Thus the voltage across the resistor is given by,

V=IR

On substituting the known values in the above equation,

\begin{gathered} 200=50000\times10^{-3}\times R \\ \Rightarrow R=\frac{200}{50000\times10^{-3}} \\ =4\text{ }\Omega \end{gathered}

Final answer:

The resistance of the resistor is 4 Ω

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andre [41]

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3 years ago
Using a density of air to be 1.21kg/m3, the diameter of the bottom part of the filter as 0.15m (assume circular cross-section),
salantis [7]

Answer:

The  drag coefficient is  D_z  =  1.30512  

Explanation:

From the question we are told that

     The density of air is  \rho_a  = 1.21 \ kg/m^3

     The diameter of bottom part is  d = 0.15 \ m

The  power trend-line  equation is mathematically represented as

      F_{\alpha }  = 0.9226 * v^{0.5737}

let assume that the velocity is  20 m/s

Then

      F_{\alpha }  = 0.9226 * 20^{0.5737}

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The drag coefficient is mathematically represented as

      D_z  =  \frac{2 F_{\alpha } }{A \rho v^2 }

Where  

     F_{\alpha } is the drag force

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       v is the flow velocity

       A is the area which mathematically evaluated as

       A = \pi r^2 =  \pi  \frac{d^2}{4}

substituting values

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Then

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   D_z  =  1.30512  

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3 years ago
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