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laiz [17]
3 years ago
8

Plants in the desert, such as the yucca tree below, tend to have very wide root structures. Some yucca tree roots have been know

n to stretch more than 10 meters away from the trunk. The plant does this so that it can have access to as much of the water that falls in that area as possible. Which of the following best explains why yucca trees rarely grow close to other large plants in the desert? A. They compete with other large plants for sunlight. B. They are able to share water with nearby plants. C. They compete with other large plants for land. D. Staying far away from other large plants keeps them cool.
Physics
2 answers:
serious [3.7K]3 years ago
5 0
C. They compete with other large plants for land. Because if they have very wide roots they will take up more land so if another one is right next to the yuca tree they might both die or one will die from lack of water. Makes sense?
Pepsi [2]3 years ago
5 0
They compete with other large plants for land (study island)
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How are waves that are created by a musical instrument and waves that
Wittaler [7]

Answer:

both caused  by physical vibrations

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3 years ago
The value of a scientific variable ____. A) can change
gregori [183]
The answer is A: can change
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3 years ago
Read 2 more answers
Two cars cover the same distance in a straight line. Car A covers the distance at a constant velocity. Car B starts from rest an
SpyIntel [72]

Answer:

a) 2.43 m/s

b) 4.83 m/s

c) 0.023 m/s²

Explanation:

a) Both cars cover a distance of 510 m in 210 s. Since car A has no acceleration

Speed = Distance / Time

\text{Speed}=\frac{510}{210}=2.43\ m/s

Velocity of car A is 2.43 m/s

t = Time taken = 210 seconds

u = Initial velocity

v = Final velocity

s = Displacement = 510 m

a = Acceleration

c)

s=ut+\frac{1}{2}at^2\\\Rightarrow 510=0\times 210+\frac{1}{2}\times a\times 210^2\\\Rightarrow a=\frac{510\times 2}{210^2}\\\Rightarrow a=0.023\ m/s^2

Acceleration of car B is 0.023 m/s²

b)

v=u+at\\\Rightarrow v=0+0.023\times 210\\\Rightarrow v=4.83\ m/s

Final velocity of car B is 4.83 m/s

6 0
3 years ago
The speed of sound in air is approximately 340 m/s. The speed of light in air is approximately 3 x 108 m/s. If 10 seconds elapse
olya-2409 [2.1K]

Answer:

3400 m

Explanation:

Both lightning and thunder happen at the same time but one is faster than the other. The distance traveled by a sound can be calculated from its speed such that;

 speed = distance/time, hence, distance = speed x time.

<em>For a thunder with 340 m/s speed and 10 seconds away from lightning, the distance between the thunder and the lightning can be calculated as</em>;

distance = 340 m/s x 10 s = 3400 m

     

3 0
3 years ago
Mars has two moons, Phobos and Deimos. Phobos orbits Mars at a distance of 9380 km from Mars's center, while Deimos orbits at 23
Sloan [31]

Answer:

The ratio is   \frac{T_1}{T_2}  = 3.965

Explanation:

From the question we are told that

   The  radius of Phobos orbit is  R_2 =  9380 km

    The radius  of Deimos orbit is  R_1  =  23500 \  km

Generally from Kepler's third law

    T^2 =  \frac{ 4 *  \pi^2 *  R^3}{G * M  }

Here M is the mass of Mars which is constant

        G is the gravitational  constant

So we see that \frac{ 4 *  \pi^2  }{G * M  } =  constant

   

    T^2 = R^3   *  constant      

=>  [\frac{T_1}{T_2} ]^2 =  [\frac{R_1}{R_2} ]^3

Here T_1 is the period of Deimos

and  T_1 is the period of  Phobos

So

      [\frac{T_1}{T_2} ] =  [\frac{R_1}{R_2} ]^{\frac{3}{2}}

=>    \frac{T_1}{T_2}  =  [\frac{23500 }{9380} ]^{\frac{3}{2}}]

=>    \frac{T_1}{T_2}  = 3.965

   

8 0
3 years ago
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