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3 years ago

Which statement is true regarding the relationship between distance and displacement

2 answers:

7 0

Distance is a scalar and equals to the total distance travelled.
Displacement is a vector and equals to the change in position. Final position - Initial position. The relationship between distance and displacement is that it is motion. The object is in motion and changes his position over time.

SpyIntel [72]3 years ago

5 0

Distance is always either the same or greater than the displacement for the same trip. Distance can never be less than displacement.

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INQUIRY IS A TYPE OF SCIENCE PROMPTED BY A QUESTION<br> TRUE OR FALSE

slamgirl [31]

The answer is clearly True

4 0

3 years ago

Read 2 more answers

Why is magnesium the limiting reactant in this experiment

Keith_Richards [23]

Answer:

Explanation:

Magnesium is being oxidized by the oxygen in the air to magnesium oxide. This is a highly exothermic combustion reaction, giving off intense heat and light. The reaction of the combustion of magnesium in oxygen is given below:

2Mg(s) + O2(g) → 2MgO(s)

The stoichiometric factor is 2 moles of magnesium are burned for every 1 mole of oxygen (2mol Mg/1mol O2). If the magnesium strip weighs 1 gram, then there is 0.04 mol of magnesium (1 gram divided by 24.3 grams/mol Mg) available in the reaction. The amount of oxygen required to completely react with the magnesium strip is:

0.04 mol Mg x (1 mol O2 / 2 mol Mg) = 0.02 mol O2 x 16 g/mol O2 = 0.32 gram O2.

The magnesium will burn until consumed entirely. There is much more oxygen available in the atmosphere than needed to consume the magnesium. Thus the magnesium is the limiting reactant because it determines the amount of product formed.

4 0

3 years ago

A horse running at 3 m/s speeds up with a constant acceleration of 5 m/s2. How fast is the

Elan Coil [88]

Answer:

The horse is going at 12.72 m/s speed.

Explanation:

The initial speed of the horse (u) = 3 m/s

The acceleration of the horse (a)= 5 m/ $s^{2}$

The displacement( it is assumed it is moving in a straight line)(s)= 15.3 m

Applying the second equation of motion to find out the time,

$s=ut+\frac{1}{2}at^{2}$

$15.3=3t+2.5t^{2}$

$2.5t^{2}+3t-15.3=0$

Solving this quadratic equation, we get time(t)=1.945 s, the other negative time is neglected.

Now applying first equation of motion, to find out the final velocity,

$v=u+at$

$v=3+1.945*5$

$v=3+9.72$

v=12.72 m/s

The horse travels at a speed of 12.72 m/s after covering the given distance.

7 0

4 years ago

an aircraft has a liftoff speed of 53 m/s. what is the minimum constant acceleration an airplane must have to reach that takeoff

xxMikexx [17]

Answer:

$a=3.34\ m/s^2$

Explanation:

<u>Accelerated Motion </u>

It refers to the motion of objects in which velocity is not constant over time. If the change of the velocity occurs at the same rate, then we say it's uniformly accelerated. Being $v_o$ = initial speed, $v_f$ = final speed, a= constant acceleration, x= distance traveled

Then, the scalar relation between them is

$v_f^2=v_o^2+2ax$

The aircraft needs to reach a liftoff speed of 53 m/s from rest (assumed) having only 420 meters to do so. We can compute the acceleration by solving for a

$\displaystyle a=\frac{v_f^2-v_0^2}{2x}$

$\displaystyle a=\frac{53^2-0^2}{2(420)}$

$\boxed{a=3.34\ m/s^2}$

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3 years ago

When the mass of one object doubles what happens to its gravitational attraction to another object of constant mass, assuming th

Gwar [14]

Gravitational force will become two times.

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3 years ago