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ra1l [238]
2 years ago
7

A ball is thrown straight up into the air from the ground with a speed of 10 m/s. What is the maximum height the ball will reach

? How much time will it take the ball to fly up and then reach the ground again?
Physics
1 answer:
Lena [83]2 years ago
6 0

Answer: 5 m, 2 s

Explanation:

gravity is roughly 10 m/s²downward

That means in one second, the velocity will have been reduced to zero

The average speed is (10 + 0) / 2 = 5 m/s

h = vt = 5(1) = 5 m

It will take as long to fall back to the thrower from rest so total flight is 1 + 1 = 2 s

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Answer:

Time taken by the arrow to travel along to hit the ground is 0.55 seconds.

Explanation:

The only "force" acting on the "crossbow" to cause it to "hit" the ground is "gravity". There is no initial velocity downward when it shoot.

d=v_{i} t+\frac{1}{2} t^{2}

d = the displacement of the object  

t = the time for which the object moved  

a = acceleration of the object  

v_i = the initial velocity of the object

Given values

d = 1.5 m

t = unknown

a=g=9.8 \mathrm{m} / \mathrm{s}^{2}

\mathrm{V}_{\mathrm{i}}=0 \mathrm{m} / \mathrm{s}

1.5 \mathrm{m}=0(\mathrm{t})+\frac{1}{2}\left(9.8 \mathrm{m} / \mathrm{s}^{2}\right) \mathrm{t}^{2}

1.5=0+4.9 \mathrm{t}^{2}

\mathrm{t}^{2}=\frac{1.5}{4.9}

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Square root both sides

t=\sqrt{0.306}

t = 0.55 s

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3 years ago
An aerobatic airplane pilot experiences weightlessness as she passes over the top of a loop-the-loop maneuver. the acceleration
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