I think the person was Galileo Galilei.
north face mask and gloves in the morning so I will not make it
No, I would not expect the lighter to work at 25 °F.
25 °F ≈ -4 °C
The boiling point of butane is -1 °C.
At -4 °C, the vapour pressure of butane is not great enough to push back against atmospheric pressure.
The lighter won't work.
Explanation:
Alkali metals forms the group 1 of the modern periodic table. They include Lithium, sodium, potassium, rubidium, cesium, and francium.
The general electronic configuration of the alkali metals -
. They have 1 valence electron.
Ionization energy is the minimum amount of energy which is required to knock out the loosely bound valence electron from the isolated gaseous atom.
<u>Thus, removal of the valence electron leads to the alkali metals having noble gas electronic configuration and which is stable. Thus, the removal of the second electron is very tough and thus, there a large increase between the first and second ionization energies of the alkali metals.</u>
A 50.0ml- volume of 0.15M HBr is titrated with 0.25M KOH . Calculate the pH after the addition of 13.0ml of KOH.
Answer: you simple have to do the following:
moles HBr = 0.0500 L x 0.15 M=0.0075
moles KOH = 0.0200 L x 0.25 M=0.0050
moles H+ in excess = 0.0075 - 0.0050= 0.0025
total volume = 0.070 L
[H+]= 0.0025/0.070=0.0357 M
pH =1.45
I hope it helps, Regards.