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blsea [12.9K]
3 years ago
13

What is the pH of a 5.09 x 10-5 M solution of NaOH?

Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
7 0

<u>Answer:</u> The pH of the solution is 9.71

<u>Explanation:</u>

1 mole of NaOH produces 1 mole of sodium ions and 1 mole of hydroxide ions.

We are given:

pOH of the solution = 7.2

To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOh of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=5.09\times 10^{-5}M

Putting values in above equation, we get:

pOH=-\log(5.09\times 10^{-5})\\\\pOH=4.29

To calculate pH of the solution, we use the equation:

pH+pOH=14\\pH=14-4.29=9.71

Hence, the pH of the solution is 9.71

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Explanation:

Applying,

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n = PV/RT............... Equation 2

From the question,

Given: P = 0.899 atm, V = 425 L, T = 24 °C = (273+24) K = 297 K.

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Substitute these values into equation 2

n = (0.899×425)/(297×0.083)

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