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3 years ago

When boiling water is the particles expanding?

1 answer:

5 0

When water is boiling the particles in the liquid are not expanding. This also applies for other liquids. Particles do not expand, it is only the volume they take up that expands. When water is boiling, the particles are rather escaping the liquid phase by undergoing a phase change which forms the particles into the gaseous phase.

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Aluminum reacts with sulfur gas to produce aluminum sulfide. a) What is the limiting reactant? What is the excess reagent? b) Ho

Sophie [7]

Answer:

a) Limiting: sulfur. Excess: aluminium.

b) 1.56g Al₂S₃.

c) 0.72g Al

Explanation:

Hello,

In this case, the initial mass of both aluminium and sulfur are missing, therefore, one could assume they are 1.00 g for each one. Thus, by considering the undergoing chemical reaction turns out:

$2Al(s)+3S_2(g)\rightarrow 2Al_2S_3(s)\\$

a) Thus, considering the assumed mass (which could be changed based on the one you are given), the limiting reagent is identified as shown below:

$n_S^{available}=1.00gS_2*\frac{1molS_2}{64gS_2} =0.0156molS_2\\n_S^{consumed\ by \ Al}=1.00gAl*\frac{1molAl}{27gAl}*\frac{3molS_2}{2molAl}=0.0556molS_2$

Thereby, since there 1.00g of aluminium will consume 0.0554 mol of sulfur but there are just 0.0156 mol available, the limiting reagent is sulfur and the excess reagent is aluminium.

b) By stoichiometry, the produced grams of aluminium sulfide are:

$m_{Al_2S_3}=0.0156molS_2*\frac{2molAl_2S_3}{3molS_2} *\frac{150gAl_2S_3}{1molAl_2S_3} =1.56gAl_2S_3$

c) The leftover is computed as follows:

$m_{Al}^{excess}=(0.0556-0.0156)molS_2*\frac{2molAl}{3molS_2}*\frac{27gAl}{1molAl} =0.72 gAl\\$

NOTE: Remember I assumed the quantities, they could change based on those you are given, so the results might be different, but the procedure is quite the same.

Best regards.

7 0

3 years ago

A group of engineers has created a biodome filled with air, plants, and animals. No material can get in or out, but sunlight can

trapecia [35]

Thx for the points lol

6 0

3 years ago

On the window sill is a potted plant. The plant always seems to lean toward the window. Even though you turn its pot around ever

ICE Princess25 [194]

Answer:

because im trynna get these 5 points

Explanation:

mklnk.m

3 0

3 years ago

A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The

True [87]

First, in order to calculate the specific heat capacity of the metal in help in identifying it, we must find the heat absorbed by the calorimeter using:
Energy = mass * specific heat capacity * change in temperature
Q = 250 * 1.035 * (11.08 - 10)
Q = 279.45 cal/g

Next, we use the same formula for the metal as the heat absorbed by the calorimeter is equal to the heal released by the metal.

-279.45 = 50 * c * (11.08 - 45) [minus sign added as energy released]
c = 0.165

The specific heat capacity of the metal is 0.165 cal/gC

6 0

3 years ago

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brainliest to whoever gets it the soonest, what SI unit do you use to measure the length of a book, and what tool and unit for t

Margarita [4]

The most appropriate SI unit used to measure the length of a book would be Centimeters.

The most appropriate SI unit to use for the volume of a book is centimeters cubed

PS: I am also a JoJo fan

7 0

3 years ago

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