Sorry, the correct answer is A. 3.4 x 10 - 24
Hope I helped ; )
Answer:
Explanation:
Word equation:
sulfuric acid + ammonium hydroxide → ammonium sulfate + water
Chemical equation:
H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O
Balanced chemical equation:
H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O
The given reaction is the reaction of acid with base. When acid and base react salt and water are produced. In given reaction an acid sulfuric acid and base ammonium hydroxide react and form ammonium sulfate salt and water. The given reaction also follow the law of conservation of mass.
Steps to balance the equation:
Steps 1;
H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O
H = 7 H = 10
S = 1 S = 1
O = 5 O = 5
N = 1 N = 2
Step 2:
H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + H₂O
H = 12 H = 10
S = 1 S = 1
O = 6 O = 5
N = 2 N = 2
Step 3:
H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O
H = 12 H = 12
S = 1 S = 1
O = 6 O = 6
N = 2 N = 2
Answer:
I think it would be A but it might be B please tell if wrong
Given:
0.060 mol of NiC2O4
Ksp = 4 x 10⁻¹⁰
1.0 L of solution
Kf of Ni(NH3)6 2⁺ = 1.2 x 10⁹
<span>NiC2O4 + 6NH3 ⇋ Ni(NH3)6 2+ + 2O4 2- </span>
<span>NiC2O4 ⇋ Ni 2+ + C2O4 2- ...Ksp </span>
<span>Ni2+ + 6NH3 ⇋ Ni(NH3)6 2+...Kf </span>
Ksp * Kf = (4 x 10⁻¹⁰) * (1.2 x 10⁹) = 0.48
K = 0.48 = [Ni(NH3)6 2+][C2O4 2-] / [NH3]⁶<span>
</span>0.48 = (0.060)² / [NH3]⁶<span> ... (dissolved C2O4 2- = 0.060M)
</span><span>[NH3]</span>⁶<span> = (0.060)</span>²<span> / 0.48 = </span>0.0036 / 0.48 = 0.0075
NH3 = ⁶√0.0075
NH3 = 0.44 M
