NaHCO3(s) --> Na2CO3 (s) + H20 (g) + CO2 (g)
1 answer:
Answer:
Explanation:
The reaction will be balanced if on each side of the equation we will have exactly same amounts of each element.
On the left, we have one sodium, on the right we have two, so we may attempt to add a coefficient of two for the reactant, sodium bicarbonate:
Now, let's calculate the number of hydrogen. We have two on the left and two on the right, so hydrogen is balanced.
A total of 2 carbons are present on the left, as well as two carbons on the right (one in sodium carbonate and one in carbon dioxide).
A total of 6 oxygens on the left and 6 on the right, so now the reaction is balanced.
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Solution:- Hypochlorite ion has one Cl and one O atom. Cl has 7 valence electrons and O has 6 valence electrons. Since there is one negative charge on the ion,
total valence electrons = 7 + 6 +1 = 14
(note:- if there is negative charge then it is added and if there is positive charge then it is subtracted while calculating the valence electrons)
Both Cl and O atoms wants to complete their octet and so for this we put a single bond between them. Single bond means two electrons, so the remaining electrons would be 14 - 2 = 12
It means 12 electrons will be placed as lone pair of electrons. To complete the octet, we put 6 dots around each of the atom. Oxygen is more electron negative than Cl, so we show the -1 charge for oxygen.
