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VLD [36.1K]
3 years ago
13

NaHCO3(s) --> Na2CO3 (s) + H20 (g) + CO2 (g)

Chemistry
1 answer:
melomori [17]3 years ago
7 0

Answer:

2~NaHCO_3 (s)\rightarrow Na_2CO_3 (s) + H_2O (g) + CO_2 (g)

Explanation:

The reaction will be balanced if on each side of the equation we will have exactly same amounts of each element.

On the left, we have one sodium, on the right we have two, so we may attempt to add a coefficient of two for the reactant, sodium bicarbonate:

2~NaHCO_3 (s)\rightarrow Na_2CO_3 (s) + H_2O (g) + CO_2 (g)

Now, let's calculate the number of hydrogen. We have two on the left and two on the right, so hydrogen is balanced.

A total of 2 carbons are present on the left, as well as two carbons on the right (one in sodium carbonate and one in carbon dioxide).

A total of 6 oxygens on the left and 6 on the right, so now the reaction is balanced.

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Hardness in groundwater is due to the presence of metal ions, primarily Mg2 and Ca2 . Hardness is generally reported as ppm CaCO
Maslowich

Answer:

  • 0.0144 M
  • 1440 ppm

Explanation:

Ca(In)²⁺ + EDTA → Ca(EDTA)²⁺ + In

We use the volume of EDTA consumed in the titration to <u>calculate the moles of Ca⁺² ions</u>:

  • 0.012 L * 0.0600 M * \frac{1molCa^{+2}}{1molEDTA} = 7.20x10⁻⁴ mol Ca⁺²

Now we <u>calculate the molarity</u>:

  • 7.20x10⁻⁴ mol Ca⁺² / 0.050 L = 0.0144 M

To calculate in ppm, we <u>use the moles of Ca⁺² and convert to mg of CaCO₃:</u>

  • 7.20x10⁻⁴ mol Ca⁺² = 7.20x10⁻⁴ mol CaCO₃
  • 7.20x10⁻⁴ mol CaCO₃ * 100g/mol * \frac{1000mg}{1g} = 72 mg CaCO₃

Finally, <u>the concentration in ppm</u> is:

  • 72 mg CaCO₃ / 0.050L = 1440 ppm
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Which of the following SI or metric units is a base unit?
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3. Ampere is the base unit for electric current.
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Using the periodic table, choose the more reactive nonmetal.<br> Te or O
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Consider the following types of electromagnetic radiation:
liq [111]

Explanation:

Electromagnetic wave              Wavelength

(1) Microwave  =   1 m to 1 mm = 10^9 nm to 10^6 nm

(2) Ultraviolet  =    10 nm to 400 nm

(3) Radio waves  =   1 mm to 100 km = 10^6 nm to 10^{14}nm

(4) Infrared  =    700 nm to 1 mm

(5) X-ray  =   0.01 nm to 10 nm

(6) Visible =   400 nm t0 700 nm

a) In order of increasing wavelength:

: 5 < 2 < 6 < 4 < 1 < 3

b) Frequency of the electromagnetic wave given as:

\nu=\frac{c}{\lambda }

\nu = frequency

\lambda = Wavelength

c = speed of light

\nu \propto \frac{1}{\lambda }

So, the increasing order of frequency:

: 3 < 1 < 4 < 6 < 2 < 5

c) Energy(E) of the electromagnetic wave is given by Planck's equation :

E=h\nu

E\propto \nu

So, the increasing order of energy:

: 3 < 1 < 4 < 6 < 2 < 5

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