NaHCO3(s) --> Na2CO3 (s) + H20 (g) + CO2 (g)
1 answer:
Answer:
Explanation:
The reaction will be balanced if on each side of the equation we will have exactly same amounts of each element.
On the left, we have one sodium, on the right we have two, so we may attempt to add a coefficient of two for the reactant, sodium bicarbonate:
Now, let's calculate the number of hydrogen. We have two on the left and two on the right, so hydrogen is balanced.
A total of 2 carbons are present on the left, as well as two carbons on the right (one in sodium carbonate and one in carbon dioxide).
A total of 6 oxygens on the left and 6 on the right, so now the reaction is balanced.
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Answer:
See explanation below
Explanation:
You forgot to put the picture to do so. In this case, I manage to find one, and I hope is the one you are looking for. If not, then post it again and I'll gladly help you out again.
According to the picture with the answer, we have a cyclohexane with 4 methyl groups there. Two of them are facing towards the molecule with a darker bond. This means that the alkyl bromide, should have a bromine in one of the bonds, and in order to produce an E2 reaction, this bromine should be facing in the opposite direction of the methyl groups which are facing towards. This is because an E2 reaction occurs with the less steric hindrance in the molecule. If the bromine is in the same direction as the methyl group, it will cause a lot more of work to do a reaction, and therefore, an E2 reaction. I will promote instead a E1 or a sustitution product.
Therefore the alkyl bromide should be like the one in the picture 2.
