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Korvikt [17]
3 years ago
6

HELP ASAP with this question.

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
8 0
D BECAUSE OF THE POSITIVE 2
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Nick opens a savings account with $50. Each week after, he deposits $15. He wants to save $500. Write and solve equation to find
Alborosie

Answer:

Equation: 500 = 50 + 15x

Step-by-step explanation:

where x is the number of weeks Nick will have to deposit $15 in order to accumulate $500, given that the first week he deposited $50.  

500 = 50 + 15x

500 = 50 + 15x

450 = 15x

x = 30

 

Now Nick will have to deposit $15 each week for 30 weeks.   This is in addition to the $50 deposit he made week 1.  So it will take him 31 total deposits to accumulate the $500.

6 0
3 years ago
My question is y = 4x + 1 and my options are<br>a. 4, 3 <br>b. 4,1<br>c. 1,4<br>d. 3,1​
Akimi4 [234]

Answer:

B. 4,1

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Suppose that θ is an acute angle of a right triangle and that sec(θ)=52. Find cos(θ) and csc(θ).
insens350 [35]

Answer:

\cos{\theta} = \dfrac{1}{52}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

Step-by-step explanation:

To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.

a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

\sec{\theta} = \dfrac{1}{\cos{\theta}}

we can substitute the value of sec(θ) in this equation:

52 = \dfrac{1}{\cos{\theta}}

and solve for for cos(θ)

\cos{\theta} = \dfrac{1}{52}

side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by \theta = \arccos{\left(\dfrac{1}{52}\right)} = 88.8^\circ

b) since right triangle is mentioned in the question. We can use:

\cos{\theta} = \dfrac{\text{adj}}{\text{hyp}}

we know the value of cos(θ)=1\52. and by comparing the two. we can say that:

  • length of the adjacent side = 1
  • length of the hypotenuse = 52

we can find the third side using the Pythagoras theorem.

(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2

(52)^2=(1)^2+(\text{opp})^2

\text{opp}=\sqrt{(52)^2-1}

\text{opp}=\sqrt{2703}

  • length of the opposite side = √(2703) ≈ 51.9904

we can find the sin(θ) using this side:

\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}

\sin{\theta} = \dfrac{\sqrt{2703}}{52}}

and since \csc{\theta} = \dfrac{1}{\sin{\theta}}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

4 0
3 years ago
Find the area of the shape below.<br> 16 cm<br> 7 cm<br> 7 cm<br> 20 cm
Ira Lisetskai [31]

Step-by-step explanation:

ar of quadilateral

=16×7×7×20

=12080cmsq

4 0
3 years ago
Read 2 more answers
In triangle opq right angled at p op=7cm,oq-pq=1 determine the values of sinq and cosq
soldi70 [24.7K]

Answer:

see explanation

Step-by-step explanation:

let pq = x

given oq - pq = 1 then oq = 1 + x

Using Pythagoras' identity, then

(oq)² = 7² + x²

(1 + x)² = 49 + x² ( expand left side )

1 + 2x + x² = 49 + x² ( subtract 1 from both sides )

2x + x² = 48 + x² ( subtract x² from both sides )

2x = 48 ( divide both sides by 2 )

x = 24 ⇒ pq = 24

and oq = 1 + x = 1 + 24 = 25 ← hypotenuse

sinq = \frac{opposite}{hypotenuse} = \frac{7}{25}

cosq = \frac{adjacent}{hypotenuse} = \frac{24}{25}



6 0
3 years ago
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