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1 year ago

C6H12O6 + 6O2 6CO2+6H2O + energy Which statement correctly compares the reactants and products of the equation?

Physics

1 answer:

ryzh [129]1 year ago

5 0

The true statement about the equation of respiration is:

The mass of the reactants is the same as the mass of the products; option C.

<h3>What is respiration?</h3>

Respiration is the process by which living organisms break down large molecules such as glucose into smaller molecules such a carbon dioxide and water to release energy in the form of ATP.

Respiration are of two types in living organisms:

Aerobic respiration which requires oxygen
anaerobic respiration that does not require oxygen

The equation of aerobic respiration is given below:

C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O + energy

In the given equation above, glucose reacts i the presence of oxygen is broken down into carbon dioxide and water and energy is released.

According to the law of conservation of mass, the mass of reactants is equal to the mass of the products.

Learn more about respiration at: brainly.com/question/22673336

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Note that the complete question is given below:

Respiration describes the process that living cells use to release energy by combining sugar and oxygen. The primary chemical changes that happen during respiration are shown in the equation below.

C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O + energy

Which statement correctly compares the reactants and products of the equation?

The mass of the reactants is less than the mass of the products.

The mass of the reactants is greater than the mass of the products.

The mass of the reactants is the same as the mass of the products.

The number of reactant molecules is greater than the number of products.

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A police car moving at 36.0 m/s is chasing a speeding motorist traveling at 30.0 m/s. The police car has a siren that emits soun

maxonik [38]

Answer:

The frequency heard by the motorist is 4313.2 Hz.

Explanation:

let f1 be the frequency emited by the police car and f2 be the frequency heard by the motorist, let v1 be the speed of the police car and v2 be the speed of the motorist and v = 343 m/s be the speed of sound.

because the police car is moving towards the motorist at a higher speed, then the motorist will hear a increasing frequency and according to Dopper effect, that frequency is given by:

f1 = [(v + v2/(v - v1))]×(f2)

= [( 343 + 30)/(343 - 36)]×(3550)

= 4313.2 Hz

Therefore, the frequency heard by the motorist is 4313.2 Hz.

5 0

3 years ago

A concrete block is hung from an ideal spring that has a force constant of 100 N/m . The spring stretches 0.129 m .A- What is th

madam [21]

Answer:

1.31498 kg

0.72050 s

Explanation:

m = Mass of block

g = Acceleration due to gravity = 9.81 m/s²

k = Spring constant = 100 N/M

x = Displacement = 0.129 m

The force balance is

$mg=kx\\\Rightarrow m=\dfrac{kx}{g}\\\Rightarrow m=\dfrac{100\times 0.129}{9.81}\\\Rightarrow m=1.31498\ kg$

The mass of the block is 1.31498 kg

Time period is given by

$T=2\pi\sqrt{\dfrac{m}{k}}\\\Rightarrow T=2\pi\sqrt{\dfrac{1.31498}{100}}\\\Rightarrow T=0.72050\ s$

The period of oscillations is 0.72050 s

The time period does not depend on the acceleration due to gravity. It varies with the mass and the spring constant.

Hence, the time period would be the same

8 0

3 years ago

Calculate the mass of wood that has the same energy as 1 g of oil

san4es73 [151]

2.3 grams of wood has the same energy as 1g of oil.

The majority of wood and wood waste used as fuel in the United States is used by industry. Manufacturers of paper and wood products are the biggest industrial users. They produce steam and electricity from waste from paper and lumber mills, which saves money by lowering the number of other fuels and electricity they need to buy to run their facilities.

There are numerous power plants that primarily burn wood to produce electricity in the electric power sector, and some coal-burning power plants burn wood chips along with coal to cut down on sulfur dioxide emissions. The primary purpose of wood consumption in the business sector is heating.

To learn more about wood please visit-

brainly.com/question/10967023

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3 0

2 years ago

Which of the following would be used in luminosity calculations?

Daniel [21]

Answer:

1) joule

2) $kgm^{2}/s^{2}$

3) $10\%$

Explanation:

1) Luminosity is the <u>amount of light emitted</u> (measured in Joule) by an object in a unit of<u> time</u> (measured in seconds). Hence in SI units luminosity is expressed as joules per second ( $\frac{J}{s}$ ), which is equal to Watts ( $W$ ).

This amount of light emitted is also called radiated electromagnetic power, and when this is measured in relation with time, the result is also called radiant power emitted by a light-emitting object.

Therefore, if we want to calculate luminosity the Joule as a unit will be used.

2) Work $W$ is expressed as force $F$ multiplied by the distane $d$ :

$W=F.d$

Where force has units of $kgm/s^{2}$ and distance units of $m$ .

If we input the units we will have:

$W=(kgm/s^{2})(m)$

$W=kgm^{2}/s^{2}$ This is 1Joule ( $1 J$ ) in the SI system, which is also equal to $1 Nm$

3) The formula to calculate the percent error is:

$\% error=\frac{|V_{exp}-V_{acc}|}{V_{acc}} 100\%$

Where:

$V_{exp}=7.34 (10)^{-11} Nm^{2}/kg^{2}$ is the experimental value

$V_{acc}=6.67 (10)^{-11} Nm^{2}/kg^{2}$ is the accepted value

$\% error=\frac{|7.34 (10)^{-11} Nm^{2}/kg^{2}-6.67 (10)^{-11} Nm^{2}/kg^{2}|}{6.67 (10)^{-11} Nm^{2}/kg^{2}} 100\%$

$\% error=10.04\% \approx 10\%$ This is the percent error

8 0

3 years ago

An airplane is flying from Dallas, Texas to Pensacola, Florida. Flying at maximum velocity, it encounters strong winds moving at

jenyasd209 [6]

Answer:

G. It will take twice as long.

Explanation:

Let's call $v$ the original speed of the plane and $d$ the distance between Dallas and Pensacola. The time the plane originally takes to complete the flight is

$t=\frac{d}{v}$

In this problem, we are told that the plane encounters wind moving at half of its speed: $\frac{v}{2}$ , in the opposite direction. This means that the new speed of the plane is

$v'=v-\frac{v}{2}=\frac{v}{2}$

And so, the time the plane takes now to complete the flight is

$t'=\frac{d}{v/2}=2\frac{d}{v}=2t$

So, the plane takes twice the time as before.

4 0

3 years ago