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3 years ago

Popular -Gra Question 16 Points 1 The unit of impulse is

1 answer:

4 0

Answer: The unit of impulse is applied to an object produces an equivalent vector change in its linear momentum, also in the same direction.

Explanation:

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What force would be required to accelerate a 1,100kg car to 0.5 m/s2

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Answer:

the force required to accelerate a 1,100kg car is 550N

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3 years ago

a train has an initial velocity of 30 m/s. If the train accelerates uniformly at a rate of 6.3 m/s ^ for 2.8 seconds what is the

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the velocity is a second final to initial velocity of 39

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2 years ago

If limestone is exposed to the right amount of heat and pressure what might it become

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3 years ago

Two workers are sliding 300 kg crate across the floor. One worker pushes forward on the crate with a force of 390 N while the ot

romanna [79]

Answer:

The crate's coefficient of kinetic friction on the floor is 0.23.

Explanation:

Given that,

Mass of the crate, m = 300 kg

One worker pushes forward on the crate with a force of 390 N while the other pulls in the same direction with a force of 320 N using a rope connected to the crate.

The crate slides with a constant speed. It means that the net force acting on it is 0. Net force acting on it is given by :

$F_1+F_2=\mu N\\\\\mu=\dfrac{F_1+F_2}{mg}\\\\\mu=\dfrac{390+320}{300\times 10}\\\\\mu=0.23$

So, the crate's coefficient of kinetic friction on the floor is 0.23.

6 0

3 years ago

If the mass of both weights is 225 gm, the first mass is located 20∘ north of east, the second mass is located 20∘ south of east

Montano1993 [528]

Answer:

The voltage is 2.114 V.

Explanation:

Given that,

Mass of both weights = 225 gm

Transducer sensitivity = 0.5 V/N

The first mass is located 20∘ north of east, the second mass is located 20∘ south of east,

We need to calculate the net equivalent force

Using formula of force

$F_{3}=m_{1}g\cos\theta+m_{2}g\cos\theta$

$F_{3}=2mg\cos\theta$

Put the value into the formula

$F_{3}=2\times0.225\times10\cos20^{\circ}$

$F_{3}=4.228\ N$

We need to calculate the voltage

Using formula of voltage

$Voltage =sensitivity\times F_{3}$

Put the value into the formula

$Voltage=0.5\times4.228$

$Voltage =2.114\ V$

Hence, The voltage is 2.114 V.

7 0

3 years ago