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blondinia [14]
3 years ago
12

Two cars leave Calgary at the same time, travelling in opposite directions. Their average speeds differ by 5 km/h. After 2 h, th

ey are 210 km apart. Find the speed of each car.
Physics
2 answers:
dimulka [17.4K]3 years ago
8 0
Let the first car's average speed be x

The second car's speed would be x+5

2(x+(x+5))=210

2x+5=105

2x=100

x=50

So the speed of the slower car is 50mph, and the speed of the faster car is 55mph


DerKrebs [107]3 years ago
3 0
I think the answer is 50 and 55 but to check that u can multiply both of them by two and then add them together and see if it = 210
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Pls help me i have to submit this due tomorrow :'D
aniked [119]

\textsf {a) As there is no change in the initial and final positions, the displacement is}\\\textsf {equal to 0.}

b) Finding total distance :

Distance travelled from 0 s to 5 s :

  • 1/2 x 5 x 30 = 75 m

Distance travelled from 5 s to 10 s :

  • 5 x 30 = 150 m

Distance travelled from 10 s to 15 s :

  • 150 + 1/2 x 5 x 5
  • 150 + 12.5 = 162.5 m

Distance travelled from 15 s to 20 s :

  • 36 x 5 + 1/2 x 5 x 4
  • 180 + 10 = 190 m

Distance travelled from 20 s to 25 s :

  • 45 x 5 + 1/2 x 5 x 5
  • 225 + 12.5 = 237.5 m

Distance travelled from 25 s to 30 s :

  • 40 x 5 + 1/2 x 10 x 5
  • 200 + 25 = 225 m

Distance travelled from 30 s to 35 s :

  • 20 x 5 + 1/2 x 20 x 5
  • 100 + 50 = 150 m

Distance travelled from 35 s to 40 s :

  • 1/2 x 20 x 5
  • 50 m

Total = 75 + 150 + 162.5 + 190 + 237.5 + 225 + 150 + 50

Total = 1240 m

c) velocity at t = 15 s

  • 36/15
  • 12/5
  • 2.4 m/s

d) average velocity

  • 0 m/s (as displacement is equal to 0)

e) average speed

  • 1240/40
  • 31 m/s

f) Part d uses displacement whereas part e uses distance

3 0
2 years ago
What is the current in a circuit if 3.50 C of charge passes any given point in a circuit in 1.80 s?
stepan [7]

Answer:

I = 1.944 A

Explanation:

<u>Given the following data;</u>

Charge, Q = 3.5C

Time, t = 1.8 secs

Charge of a substance is given by the formula;

Q = It

Where;

Q is the amount of charge measured in Colombs.

I is the current measured in Amperes.

t is the time measured in seconds.

Making I the subject of formula, we have

I = \frac {Q}{t}

I = \frac {3.5}{1.8}

I = 1.944 A

Therefore, the current in the circuit is 1.944 Amperes.

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Answer:

I know only one type of light that is absorbed by genetic materail and that is UV light

Explanation:

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