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Molodets [167]
4 years ago
5

Given the incomplete equation 4Al + 3O2 → 2X, what compound is X?

Chemistry
2 answers:
Sever21 [200]4 years ago
8 0
<h3><u>Answer</u>;</h3>

B) Al2O3

<h3><u>Explanation;</u></h3>

Aluminium reacts with oxygen to form aluminium oxide.

The chemical reaction for the reaction between Aluminium and Oxygen is;

4Al+ 3O₂→ 2Al₂O₃

Therefore;

Compound X is Aluminium oxide (Al₂O₃)

kifflom [539]4 years ago
5 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

When aluminium metal reacts with air, it produces an oxide named as aluminium oxide. The chemical formula for this compound is Al_2O_3

The balanced chemical equation for the above reaction follows:

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)

By Stoichiometry of the reaction:

4 moles of aluminium metal reacts with 3 moles of oxygen to produce 2 moles of aluminium oxide.

This reaction is a type of synthesis reaction because substances are reacting in their elemental state to produce one compound.

Hence, the correct answer is Option B.

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If the net force on a object is 375 N to the right, in what direction will the object move?
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Why is carbon ideal for making different compounds?
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Gold has a density of 19.32 is this a chemical change or physical change
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A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp
vichka [17]

Answer:

The balanced chemical equation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = T_1= 21.36^oC

Final temperature of the calorimeter = T_2= 26.37^oC

Heat absorbed by calorimeter = Q

Q=C\times \Delta T

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol

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