3 years ago

The thrust from a car is 590 N. The air resistance and friction together total 680 N. What happens to the speed of the car?

1 answer:

5 0

The net force in the direction the car is traveling (forward) is

(590 - 680) = -90N = 90 newtons backwards.

The car accelerates backwards at the rate of (90/its mass) m/sec-squared.

Another way to look at it: The car's forward speed decreases at that rate.

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The type of function that describes the amplitude of damped oscillatory motion is _______. The type of function that describes t

Salsk061 [2.6K]

Answer:

exponential

Explanation:

type of function that describes the amplitude of damped oscillatory motion is exponential because as we know that here function is

y = A × $e^{\frac{-bt}{2m}}$ × cos(ωt + ∅ ) ..................................... ( 1 )

here function A × $e^{\frac{-bt}{2m}}$ is amplitude

as per equation ( 1 )it is exponential

so that we can say that amplitude of damped oscillatory motion is exponential

8 0

2 years ago

We can expect the force of friction to be greater for an object moving on a surface if the surfaces in contact are

nikitadnepr [17]

Answer:

Explanation:

Friction is caused by how rough and object is, and how much the object weighs, as this causes it to drag more.

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1 year ago

A 2,294N force is applied to a 408kg mass. What is the acceleration of the mass?

Nataly_w [17]

Answer:

5.622

Explanation:

a=F/M

a=2294/408

a=5.622

8 0

2 years ago

How much work is done on a small car if a 3150 N force is exerted to move it 75.5 m to the side of the road

irinina [24]

Answer:

Explanation:

Work = Force times displacement. Therefore,

W = 3150(75.5) so

W = 238000 N*m

6 0

1 year ago

If a town was 90 miles away and you travel at 45 mph how long would it take to get there

notka56 [123]

Answer:

t = 2 hours

Explanation:

Given that,

Distance of the town, d = 90 miles

Speed, v = 45 mph

We need to find the time to get there. The speed of an object is given by :

$v=\dfrac{d}{t}$

Where

t is time

$t=\dfrac{d}{v}\\\\t=\dfrac{90}{45}\\\\t=2\ h$

So, the required time is 2 hours.

5 0

2 years ago