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Minchanka [31]
4 years ago
14

The thrust from a car is 590 N. The air resistance and friction together total 680 N. What happens to the speed of the car?

Physics
1 answer:
vaieri [72.5K]4 years ago
5 0

The net force in the direction the car is traveling (forward) is

               (590 - 680) = -90N = 90 newtons backwards.

The car accelerates backwards at the rate of (90/its mass) m/sec-squared.

Another way to look at it:  The car's forward speed decreases at that rate.


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The slope of a Velocity versus Time graph will tell you the object’s what?
Verizon [17]
Hope it helped you.

My name is Charlie.

Today this question is about science,or chemistry.

A. Acceleration is a correct answer. Acceleration is a rate of change in velocity. 

It change in velocity/change in time. Next, to slope will be indicated by the acceleration.

B Change in position is a incorrect answer.

C. Velocity is a incorrect answer. Velocity is a displacement of an object during a specific unit of time. It can used two measurements are needed to determine velocity. It displacement or by the time. Displacement it includes a direction, so the velocity will also includes a direction. It can used speed with direction. Velocity it can be average velocity or an instantaneous velocity.

-Charlie

Have a great day!

Thanks!
7 0
3 years ago
What is physics and biology​
lorasvet [3.4K]

Answer:Biology is the study of living organisms. Physics is the study of matter and the laws of nature to understand the behavior of matter and the universe. The Biophysical Society explains that, when scientists combine physics and biology, they learn more about biological systems on a molecular or atomic level.

Explanation:

8 0
3 years ago
A water wave of wavelength 859 cm travels a distance of 64 m in a time of 14 s. What is the period of the wave, in units of seco
swat32

Answer:

1.87 s

Explanation:

d = distance traveled by the water wave = 64 m

t = time taken to travel the distance = 14 s

v = speed of water wave

Speed of water wave is given as

v=\frac{d}{t}

v=\frac{64}{14}

v = 4.6 m/s

\lambda = wavelength of the wave = 859 cm = 8.59 m

T = period of the wave

period of the wave is given as

T = \frac{\lambda }{v}

T = \frac{8.59 }{4.6}

T = 1.87 s

8 0
3 years ago
A race is held between a sports car and a motorcycle. The sports car can accelerate at 5.0 m/s^2 and the motorcycle can accelera
user100 [1]

Answer:

Vf₁ = 30 m/s

s₂ = 90 m

car wins the race.

Explanation:

To find the speed of car after 5 s, we use 1st equation of motion:

Vf₁ = Vi₁ + a₁t₁

where,

Vf₁ = Final Speed of Car = ?

Vi₁ = Initial Speed of Car = 0 m/s

a₁ = acceleration of car = 5 m/s²

t₁ = time = 5 s

Therefore,

Vf₁ = 0 m/s + (5 m/s²)(5 s)

<u>Vf₁ = 25 m/s</u>

<u></u>

To find the distance of motorcycle after 6 s, we use 2nd equation of motion:

s₂ = Vi₂ t₂ + (1/2)a₂t₂²

where,

s₂ = distance covered by the motorcycle = ?

Vi₁ = Initial Speed of motorcycle = 0 m/s

a₂ = acceleration of motorcycle = 8 m/s²

t₂ = time = 6 s

Therefore,

s₂ = (0 m/s)(6 s) + (1/2)(5 m/s²)(6 s)²

<u>s₂ = 90 m</u>

<u></u>

We can use 2nd equation of motion to find time taken by each car and motorcycle to reach the finish point:

For Car:

s₁ = Vi₁ t₁ + (1/2)a₁t₁²

where,

s₁ = 200 m - 50 m = 150 m (since, car starts 50 m ahead)

Therefore.

150 m = (0 m/s)(t₁) + (1/2)(5 m/s²)t₁²

t₁ = √60 s²

t₁ = 7.74 s

For Motorcycle:

s₂ = Vi₂ t₂ + (1/2)a₂t₂²

where,

s₁ = 200 m

Therefore.

200 m = (0 m/s)(t₂) + (1/2)(5 m/s²)t₂²

t₂ = √80 s²

t₂ = 8.94 s

Since, the car takes less time to reach finish line.

Therefore, car wins the race.

5 0
3 years ago
In the Niagara Falls hydroelectric generating plant, the energy of falling water is converted into electricity. The height of th
Charra [1.4K]

Answer:

1960.32306 kg/s

Explanation:

m = Mass of water = 1 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Height from which the water will fall

Potential Energy

PE=mgh\\\Rightarrow PE=1\times 9.81\times 52\\\Rightarrow PE=510.12\ J

One megawatts of power is required

So, flow rate

\dotm=\frac{P}{PE}\\\Rightarrow \dotm=\frac{1\times 10^6}{510.12}\\\Rightarrow \dotm=1960.32306\ kg/s

1960.32306 kg/s is required to produce a megawatt of power

7 0
3 years ago
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