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Minchanka [31]
4 years ago
14

The thrust from a car is 590 N. The air resistance and friction together total 680 N. What happens to the speed of the car?

Physics
1 answer:
vaieri [72.5K]4 years ago
5 0

The net force in the direction the car is traveling (forward) is

               (590 - 680) = -90N = 90 newtons backwards.

The car accelerates backwards at the rate of (90/its mass) m/sec-squared.

Another way to look at it:  The car's forward speed decreases at that rate.


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6 0
3 years ago
The rectangular coils in a 345-turn generator are 12 cm by 12 cm. Part A
Likurg_2 [28]

Answer:

118.166 volt

Explanation:

We have given number of turns N =345

Sides of the rectangular coils is 12 cm =0.12 m

So area A =0.12×0.12=0.0144 m^2

Magnetic field B =0.45 T

Angular speed =505 rpm

Speed in rad/sec \omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 505}{60}=52.8566rad/sec

The emf is given by E=NAB\omega SIN\omega t

For maximum emf sinwt =1

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4 0
3 years ago
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Answer:

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3 years ago
A flywheel flows from 250rpm to 150rpm in 4.2 seconds. How many revolutions occur during this time ​
Assoli18 [71]

Answer:

7revolutions

Explanation:

Given parameters:

Initial revolution  = 250rpm

Final revolution  = 150rpm

Time  = 4.2s

Unknown:

Number of revolutions that occur at this time = ?

Solution:

To solve this problem;

 let us find the change in revolution  = 250rpm - 150rpm  = 100rpm

Convert the time to seconds;

         60s makes 1 minute

        4.2s will make \frac{4.2}{60}   = 0.07min

So;

      The number of revolutions at this time  = 100rpm x 0.07min

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