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3 years ago

The thrust from a car is 590 N. The air resistance and friction together total 680 N. What happens to the speed of the car?

1 answer:

5 0

The net force in the direction the car is traveling (forward) is

(590 - 680) = -90N = 90 newtons backwards.

The car accelerates backwards at the rate of (90/its mass) m/sec-squared.

Another way to look at it: The car's forward speed decreases at that rate.

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2 years ago

What is the equivalent resistance of a circuit that contains four 75.0 resistors connected in parallel with a 100.0 V battery?

zhannawk [14.2K]

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3 years ago

Read 2 more answers

A series RCL circuit is at resonance and contains a variable resistor that is set to 206Ω. The power dissipated in the circuit i

mash [69]

Answer:

Power dissipated in resistor 532 ohm is 0.503 watt

Explanation:

We have given in first case resistance $R_1=206ohm$

Power dissipated in this resistance is $P_1=1.30watt$

Power dissipated in the resistor is equal to $P=\frac{v_{rms}}^2{R}$

We have to find the power dissipated in the resistor is 1.30 watt

From the relation we can say that $\frac{P_1}{P_2}=\frac{R_2}{R_1}$

$\frac{1.3}{P_2}=\frac{532}{206}$

$P_2=0.503watt$

So power dissipated in resistor 532 ohm is 0.503 watt

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kondor19780726 [428]

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