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Maksim231197 [3]
3 years ago
14

C12H22O11 + 11H2SO4 12C + 11H2SO4 + 11H2O

Physics
1 answer:
Nataly_w [17]3 years ago
7 0
By looking at the equation 
<span>C12H22O11 + 11H2SO4 12C + 11H2SO4 + 11H2O
we can conclude that the concentrated sulfuric acid is a catalyst because
</span><span>the sulfuric acid doesn't react with the reactant and it is not consumed.

Hope this helps! If you have any other questions or would like further explanation just let me know!! :)
</span>
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if two point charges are separated by 1.5 cm and have charge values of 2.0 and -4.0, respectively, what is the value of the mutu
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Complete question:

if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.

Answer:

The mutual force between the two point charges is 319.64 N

Explanation:

Given;

distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m

value of the charges, q₁ and q₂ = 2 μC and - μ4 C

Apply Coulomb's law;

F = \frac{k|q_1||q_2|}{r^2}

where;

F is the force of attraction between the two charges

|q₁| and |q₂| are the magnitude of the two charges

r is the distance between the two charges

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

F = \frac{k|q_1||q_2|}{r^2} \\\\F = \frac{8.99*10^9 *4*10^{-6}*2*10^{-6}}{(1.5*10^{-2})^2} \\\\F = 319.64 \ N

Therefore, the mutual force between the two point charges is 319.64 N

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Answer:

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