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Maksim231197 [3]
3 years ago
14

C12H22O11 + 11H2SO4 12C + 11H2SO4 + 11H2O

Physics
1 answer:
Nataly_w [17]3 years ago
7 0
By looking at the equation 
<span>C12H22O11 + 11H2SO4 12C + 11H2SO4 + 11H2O
we can conclude that the concentrated sulfuric acid is a catalyst because
</span><span>the sulfuric acid doesn't react with the reactant and it is not consumed.

Hope this helps! If you have any other questions or would like further explanation just let me know!! :)
</span>
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Which formula is used to find an object’s acceleration?
marissa [1.9K]

Answer:

Δv/Δt

Explanation:

I beat your game SAW.

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2 years ago
What is the equation for calculating the heat energy released during heating effect of electric current?
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The heat energy released from a piece of wire or any other section of a circuit is:

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A 65.8-kg person throws a 0.0413 kg snowball forward with a ground speed of 32.5 m/s. A second person, with a mass of 58.7 kg, c
guapka [62]

Answer:

v_{1} = 2.490\,\frac{m}{s}

v_{2} = 0.023\,\frac{m}{s}

Explanation:

The statement is described physically by means of the Principle of Momentum Conservation. Let assume that first person moves in the positive direction:

First Person

(65.8\,kg)\cdot (2.51\,\frac{m}{s}) = (65.8\,kg)\cdot v_{1} + (0.0413\,kg)\cdot (32.5\,\frac{m}{s} )

Second Person

(0.0413\,kg)\cdot (32.5\,\frac{m}{s})+(58.7\,kg)\cdot (0\,\frac{m}{s})=(0.0413\,kg+58.7\,kg)\cdot v_{2}

The final velocities of the two people after the snowball is exchanged is:

v_{1} = 2.490\,\frac{m}{s}

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6 0
3 years ago
When a second student joins the first, the height difference between the liquid levels in the right and left pistons is 40 cm .
vlada-n [284]

Answer:

m = 56.5 kg

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Δm*g / Area = p * g * Δh   ..... Eq1

m = \frac{p*h*A}{g}

m = \frac{850 * 0.4 * pi*0.46^2}{4*9.81}\\\\m= 56.5 kg

8 0
2 years ago
An oil gusher shoots crude oil 25.0 m into the air through a pipe with a 0.100-m diameter. Neglecting air resistance but not the
Mariana [72]

Answer:3764.282 KPa

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i.e. the velocity of jet is

v=\sqrt{2gh}[/tex]

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4 0
3 years ago
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