Answer:
Potential energy, E = 25 mgh
Explanation:
Given that,
Mass of the object, m = 5 m
It is lifted to a height of, h = 5 h
It is required to find the potential energy gained by the object. It is given by the product of object's mass, acceleration due to gravity and heigh above ground. It is given by :
E = 25 mgh
So, the potential energy gained by the object is (25 mgh). Hence, this is the required solution.
Answer:
v = 17.66 m/s
Explanation:
As we know that the lower end of the pole is fixed in the ground and it start rotating about that end
so here we can say that the gravitational potential energy of the pole will convert into rotational kinetic energy of the pole about its one end
so we have

so we have

now we have


now the speed of the other tip of the pole is given as

