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zimovet [89]
2 years ago
13

A spaceship departs from Earth for the star Alpha Centauri, which is 4.37 light-years away. The spaceship travels at 0.70c. 1) W

hat is the time required to get there as measured by a passenger on the spaceship
Physics
1 answer:
Nutka1998 [239]2 years ago
7 0

Answer:

Time = 6.243 years = (1.97 × 10⁸) s

Explanation:

Speed = (Distance)/(Time)

Time = (Distance)/(Speed)

Distance = 4.37 light years = 4.37 × c × years

Time = (4.37 c.years)/(0.7c)

Time = 6.243 years = (1.97 × 10⁸) s

Hope this Helps!!!

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3 years ago
Identical isolated conducting spheres 1 and 2 have equal charges and are separated by a distance that is large compared with the
scoundrel [369]

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F = 0.1575 N

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In this moment then

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Sphere three has a charge = Q/2

Now when the third sphere touches the second sphere again the charge is distributed in a manner that both sphere has the same charge.

How the total charge is Q = Q/2 + Q = 3/2Q, when the spheres are separated each one has 3/4Q

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