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zimovet [89]
3 years ago
13

A spaceship departs from Earth for the star Alpha Centauri, which is 4.37 light-years away. The spaceship travels at 0.70c. 1) W

hat is the time required to get there as measured by a passenger on the spaceship
Physics
1 answer:
Nutka1998 [239]3 years ago
7 0

Answer:

Time = 6.243 years = (1.97 × 10⁸) s

Explanation:

Speed = (Distance)/(Time)

Time = (Distance)/(Speed)

Distance = 4.37 light years = 4.37 × c × years

Time = (4.37 c.years)/(0.7c)

Time = 6.243 years = (1.97 × 10⁸) s

Hope this Helps!!!

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Answer:

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Explanation:

From the question we are told that

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=>   a =  -4.116 m/s^2

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Here  v =  0 m/s since it came to a stop

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 =>   s=  \frac{0 -(15.8)^2 }{ - 2 * 4.116}

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