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zimovet [89]
3 years ago
13

A spaceship departs from Earth for the star Alpha Centauri, which is 4.37 light-years away. The spaceship travels at 0.70c. 1) W

hat is the time required to get there as measured by a passenger on the spaceship
Physics
1 answer:
Nutka1998 [239]3 years ago
7 0

Answer:

Time = 6.243 years = (1.97 × 10⁸) s

Explanation:

Speed = (Distance)/(Time)

Time = (Distance)/(Speed)

Distance = 4.37 light years = 4.37 × c × years

Time = (4.37 c.years)/(0.7c)

Time = 6.243 years = (1.97 × 10⁸) s

Hope this Helps!!!

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Why does Mars not have an electric field and why
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Answer:

The difference lies in the planets' respective magnetic fields, because while Earth's magnetism comes from within, Mars' does not. Earth's magnetism comes from its core, where molten, electrically conducting iron flows beneath the crust. Its magnetic field is global, meaning it surrounds the entire planet

Explanation:

thanks for question

7 0
2 years ago
a boy takes 15min to reach his school on bicycle.if the bicycle have speed of 2m/s the what is the distance between the house an
11111nata11111 [884]
When looking for distance you multiply speed by time

So 15 x 2 = 30

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6 0
3 years ago
A golfer is on the edge of a 12.5 m bluff overlooking the 18th hole which is located 60 m from the base of the bluff. She launch
Lina20 [59]

Answer:

The ball impact velocity i.e(velocity right before landing) is 6.359 m/s

Explanation:

This problem is related to parabolic motion and can be solved by the following equations:

x=V_{o}cos \theta t----------------------(1)

y=y_{o}+V_{o} sin \theta t - \frac{1}{2}gt^{2}---------(2)

V=V_{o}-gt ----------------------- (3)

Where:

x = m is the horizontal distance travelled by the golf ball

V_{o} is the golf ball's initial velocity

\theta=0\° is the angle (it was  a horizontal shot)

t is the time

y is the final height of the ball

y_{o} is the initial height of the ball

g is the acceleration due gravity

V is the final velocity of the ball

Step 1: finding t

Let use the equation(2)

t=\sqrt{\frac{2 y_{o}}{g}}

t=\sqrt{\frac{2 (12.5 m)}{9.8 m/s^{2}}}

t=1.597s

Substituting (6) in (1):

67.1 =V_{o} cos(0\°) 1.597-------------------(4)

Step 2:  Finding V_{o}:

From equation(4)

67.1 =V_{o}(1) 1.597

V_0 = \frac{6.71}{1.597}

V_{o}=42.01 m/s (8)  

Substituting V_{o} in (3):

V=42.01 -(9.8)(1.597)

v =42 .01 - 15.3566  

V=26.359 m/s

5 0
2 years ago
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Answer:

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Explanation:

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