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Art [367]
3 years ago
5

What is the correct electron-dot formula for Sulfur?

Chemistry
1 answer:
const2013 [10]3 years ago
7 0

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A patient is prescribed 100.0 mg/day of antibiotic for
Rufina [12.5K]

Answer:

70

Explanation:

20 x 5 vials = 100mg

therefore 5 vials required each day.

Two weeks = 14 days

14 days x 5 vials = 70 vials

4 0
3 years ago
Titanium(IV) chloride decomposes to form titanium and chlorine, like this:
Lesechka [4]

The full question is shown in the image attached to this answer

Answer:

6.2 * 10^-3

Explanation:

The reaction at equilibrium is as follows;

TiCl4(l) → Ti(s)+ 2Cl2(g)

We have to obtain the concentration of chlorine gas as follows;

[Cl2] = 1.08/70.91 g/mol × 5.2 L

[Cl2] = 0.079 M

Kc = [Cl2]^2

Kc = [ 0.079]^2

Kc = 6.2 * 10^-3

4 0
3 years ago
A 283.3-g sample of X2(g) has a volume of 30 L at 3.2 atm and 27 'C. What is element X?
professor190 [17]

we find the number of moles with the formula

pV=nRT

27C=300k

3.2*30=n*0.082*300

n=96/24.6=3.9 moles

we have the mass ant the number of moles so we can calculate the molar mass

283.3/3.9=72.64g/moles

that means X's mass is 72.64/2=36.3 so the element is Kr(Kriptonium)

4 0
3 years ago
Quinine (C20H24N2O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine
dolphi86 [110]

Answer:

The pH of saturated solution of the quinine is 10.05

Explanation:

Quinine (Q) is C20H24N2O2 has a molar mass of 324.4 g/mol

Q can behave as a weak base. Kb and pKb can be calculated for weak bases

pKb1 is to be considered when solving the question.

pKb1 = 5.1

Step 1 : Calculate the Kb of Quinine

            pKb1 = - log [kb]

                5.1  = - log [kb]

                take Antilog of both side

             [kb] = 7.94 x 10∧-6

Step 2: Calculate the concentration of saturated solution of Q in mol/dm3

           From the question, 1900 ml of solution contains 1 g of Q

           Therefore,  1000 ml of solution will contain........... x g of Q

           x = 1000 /1900

           x = 0.526 g in 1 dm3

In calculating concentration in mol/dm3,

Concentration in mol/dm3 = concentration in g /dm3 divided by molar mass

Molar mass of Q = 324.4

Concentration in mol/dm = 0.526 /324.4

                                         = 0.0016 mol/dm3

Step 3: Calculating the Concentration of OH-

            At Equilibrium, Kb = x² / 0.0016

            7.94 x 10∧-6 = x² / 0.0016

            x = √ 0.0016 × 7.94 x 10∧-6

            x = 1. 127 × 10∧-4 mol/dm3

The concentration of OH- = 1. 127 × 10∧-4 mol/dm

Step 4:  Calculating the pH of Quinine

           Recall, pOH = - log [OH-]

           pOH = - log [1. 127 × 10∧-4]

           pOH = 3.948

           Also recall that pH + pOH = 14

           pH = 14 - 3.948

           pH = 10.05

           

8 0
4 years ago
Choose the statement below that is TRUE.
Leni [432]

Answer: Option (a) is the correct answer.

Explanation:

A weak acid is defined as an acid that dissociates partially when dissolve in water or a polar solvent.

For example, acetic acid is a weak acid and when dissolved in water it dissociates partly into ions as follows.

         CH_{3}COOH(aq) \rightleftharpoons CH_{3}COO^{-}(aq) + H^{+}(aq)

And, a strong acid is defined as an acid which when dissolved in water dissociates completely into ions.

For example, HCl is a strong acid and when dissolved in water it dissociates completely.

       HCl \rightarrow H^{+} + Cl^{-}

Thus, we can conclude that the statement a weak acid solution consists of mostly non-ionized acid molecules, is true.

7 0
3 years ago
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