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Ipatiy [6.2K]
3 years ago
10

Consider a horizontal layer of the dam wall of thickness dx located a distance x above the reservoir floor. What is the magnitud

e dF of the force on this layer that results from adding the water to the reservoir? Express your answer in terms of x, dx, the magnitude of the acceleration due to gravity g, and any quantities from the problem introduction.

Physics
1 answer:
adoni [48]3 years ago
6 0

Answer:

Explanation:

Attached is the solution

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How far apart are two conducting plates that have an electric field strength of 4. 4 kv/m between them, if their potential diffe
IRINA_888 [86]

Conducting plates will be 3.75 m apart if an electric field strength of 4. 4 kV/m between them, if their potential difference is 15 kV

The potential difference, also referred to as voltage difference between two given points is the work in joules required to move one coulomb of charge from one point to the other. The SI unit of voltage is the volt. Volt Formula.

In a simple parallel-plate capacitor, a voltage applied between two conductive plates creates a uniform electric field between those plates. The electric field strength in a capacitor is directly proportional to the voltage applied and inversely proportional to the distance between the plates.

E = V/d

E = Electric field strength

d = distance between the plates

V = potential difference

Electric field strength = 4 kV/m

Potential difference  =  15 kV

d = V / E =  15 kV / 4 kV/m

  = 3.75 m

To learn more about capacitor here

brainly.com/question/17176550

#SPJ4

6 0
2 years ago
Scientists use laser range-finding to measure the distance to the moon with great accuracy. A brief laser pulse is fired at the
Fofino [41]

Answer:

d = 2,042 10-3 m

Explanation:

The laser diffracts in the circular slit, so the process equation is

      d sin θ= m λ

The first diffraction minimum occurs for m = 1

We can use trigonometry in the mirror

        tan θ = Y / L

Where L is the distance from the Moon to Earth

Since the angle is extremely small

           tan θ = sin θ / cos θ

           Cos θ = 1

           tant θ = sin θ = y / L

We replace

           d y / L = λ

           d = λ L / y

Let's calculate

           d = 532 10⁻⁹ 3.84 10⁶/1 10³

           d = 2,042 10-3 m

5 0
2 years ago
Water flows from the bottom of a storage tank at a rate of r(t) = 300 − 6t liters per minute, where 0 ≤ t ≤ 50. Find the amount
SSSSS [86.1K]

r(t) models the water flow rate, so the total amount of water that has flowed out of the tank can be calculated by integrating r(t) with respect to time t on the interval t = [0, 35]min

∫r(t)dt, t = [0, 35]

= ∫(300-6t)dt, t = [0, 35]

= 300t-3t², t = [0, 35]

= 300(35) - 3(35)² - 300(0) + 3(0)²

= 6825 liters

7 0
3 years ago
Which of the following power plants does not use thermal energy to produce electricity?
Delvig [45]

Answer: d

Explanation:

4 0
2 years ago
A radar antenna is tracking a satellite orbiting the earth. At a certain time, the radar screen shows the satellite to be 118 km
ruslelena [56]

Answer:

x component 60.85 m

y component 101.031 m

Explanation:

We have given distance r = 118 km

Angle which makes from ground = 58.9°

(a) X component of distance  is given by r_x=rcos\Theta =118\times cos58.9=118\times 0.5165=118=60.85m

(b) Y component of distance is given by r_Y=rcos\Theta =118\times sin58.9=118\times 0.8562=101.0316m

These are the x and y component of position vector

6 0
3 years ago
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