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sergey [27]
3 years ago
12

7. What is the volume of 64.0 g of benzene?

Chemistry
1 answer:
erastova [34]3 years ago
5 0

Answer:

Volume of benzene is 73.23 mL.

Explanation:

Given data:

Volume of benzene = ?

Mass of benzene = 64.0 g

Solution:

The given problem will be solved through density formula.

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

The value of density of benzene in literature is 0.874 g/mL.

0.874 g/mL = 64.0 g/ v

v = 64.0 g/0.874 g/mL

v = 73.23 mL

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Answer:

2-chloro-4-methylpentanal.

Explanation:

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In this case, according to the chemical compound:

CH3-CH-CH2-CH-CHO

          |              |

        CH3        Cl

We can see the main functional group is an starting carbonyl, which means this is an aldehyde. Moreover, we can see a Cl-substituent on the second carbon and a methyl substituent on the fourth carbon. Therefore, the IUPAC name turns out: 2-chloro-4-methylpentanal.

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suter [353]

Answer: The possible molecular formula will be CO_2

Explanation:

Mass of C= 27.3 g

Mass of O = 72.7 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{27.3g}{12g/mole}=2.275moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{72.7g}{16g/mole}=4.544moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{2.275}{2.275}=1

For O =\frac{4.544}{2.275}=2

The ratio of C : O = 1: 2

Hence the empirical formula is CO_2

The possible molecular formula will be=n\times CO_2

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