The heat required to increase the temperature of 1.20 g of water is 80,256 k/j
<h3>What is specific heat?</h3>
The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.
4. 18 J heat is required to change the temperature of 1.20 kg of water from 23. 00 °c to 39. 00 °c.
The heat required to raise temperature is the product of mass, specific heat and temperature change
1,200 × 4.18 × (39 − 23) = 80,256
Thus, the heat required to increase the temperature of 1.20 g of water is 80,256 k/j
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Which atoms? ~~~~~~~~~~~~~~~~~~~~~~~~~`
Answer:The mole ratio is A:B:A+B
Explanation:when substance reacts according to John Dalton's theory,their combining ratio is often a replica of the combining moles of the reactants and that of the products. So when Amoles of X combines withB moles of Y ,they produce A+B moles of XY to get a balance reaction e.g if 1moles of X2 reacts with 1moles of Y2 to form XY
The balance equation is seen as
X2+Y2_____2XY
Answer:
130.1 x 10²³ molecules of sugar
Explanation:
One dozen = 12 donuts
1 doughnut = 1.8 moles of sugar
12 doughnut = (1.8 x 12) moles of sugar = 21.6 moles of sugar
1 mole of any substance contains Avogadro’s number (6.023 x 10²³) of molecules.
1 mole of sugar = 6.023 x 10²³ molecules of sugar
21.6 moles of sugar = (6.023 x 10²³ x 21.6) molecules of sugar
= 130.1 x 10²³ molecules of sugar
