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3 years ago

14

Calculate the pH when the following quantities of 0.100 M NaOH solution have been added to 50.0 mL of 0.100 M HCl solution: (a)

49.0 mL, (b) 51.0 mL

1 answer:

yuradex [85]3 years ago

7 0

Answer:

!

Explanation:

ned help too^^

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Use the combined gas law to calculate the "corrected" volume of hydrogen at STP

solong [7]

Answer:

We will derive the combined gas equation from the law of Gases

Boyle's law

P∝1/V

PV=Constant

Charles law

V∝T

Avogadro's Law

V∝n

By combining these three equations we get the combined gas equation

PV=nRT

V=nRT/P

If n=1 mole

V=RT/P

By putting the value of R, T, and P in the above equation we can calculate the volume of the gas at STP.

4 0

3 years ago

A 125g metal block at a temperature of 93.2 degrees Celsius was immersed in 100g of water at 18.3 degrees Celsius. Given the spe

ivann1987 [24]

Answer:

Final temperature is 34.2 °C

Explanation:

Given data:

mass of metal = 125 g

temperature of metal = 93.2 °C

mass of water v= 100 g

temperature of water = 18.3 °C

specific heat of meta is = 0.900 j/g. °C

specific heat of water is = 4.186 j/g. °C

final temperature of water and metal = ?

Solution:

Q = m . c . ΔT

ΔT = T2-T1

now we will put the values in equation

Q1 = m . c . ΔT

Q1 = 125 g. 0.900 j/g. °C .93.2°C - T2

Q1 = 112.5 (93.2°C - T2)

Q1 =10,485 - 112.5T2

Q2 = m . c . ΔT

Q2 = 100 . 4.186. (T2- 18.3)

Q2 = 418.6 . (T2- 18.3)

Q2 = 418.6T2 - 7660.38

10,485 - 112.5T2 = 418.6T2 - 7660.38

10,485 + 7660.38 = 418.6T2+ 112.5T2

18145.38 = 531.1 T2

T2 = 18145.38/531.1

T2 = 34.2 °C

3 0

3 years ago

Need help !!!!! ASAP

Korolek [52]

<h2>Hello!</h2>

The answer is:

The new volume is 2.84 L.

$V_{2}=2.84L$

<h2>Why?</h2>

To solve the problem, we need to remember what STP means. STP means that the gas is at standard temperature and pressure, or 273.15 K (0°C) and 1 atm.

Also, we need to use the Combined Gas Law, since the temperature, the pressure and the volume are being changed.

The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using , Gay-Lussac's Law, Charles's Law, and Boyle's Law.

The law is defined by the following equation:

$\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}$

Where,

$P_{1}$ is the first pressure.

$V_{1}$ is the first volume.

$T_{1}$ is the first temperature.

$P_{2}$ is the second pressure.

$V_{2}$ is the second volume.

$T_{2}$ is the second temperature.

So, we are given the following information:

$V_{1}=2L\\P_{1}=1atm\\T_{1}=0\°C=273.15K\\P_{2}=80kPa=0.8atm\\T_{2}=37\°C=37+273=310K$

Then, isolating the new volume, and substituting, we have:

$\frac{P_{1}V{1}}{T_{1}}=\frac{P_{2}V{2}}{T_{2}}\\\\V_{2}=\frac{P_{1}V{1}}{T_{1}}*\frac{T_{2}}{P_{2}}\\\\V_{2}=\frac{1atm*2L}{273.15K}*\frac{310K}{0.8kPa}=2.84L$

Hence, the new volume is 2.84 L.

$V_{2}=2.84L$

Have a nice day!

4 0

4 years ago

In 0.4 mole of H2S, how many atoms of H are there?

Debora [2.8K]

Answer:

8

Explain

H: Ignoring the coefficient, we know there's 5+3=8 atoms

5 0

3 years ago

Balance the chemical equation given below, and determine the number of grams of MgO that are needed to produce 20.0 g of Fe2O3.

Alenkasestr [34]

Answer:

1.) The balanced equation is 3MgO(s) + 2Fe(s) ===> Fe2O3(s) + 3Mg(s)

2.) 20g of Fe2O3 will be produced by 20 ×120/160 = 15g of MgO

Explanation:

THE CORRECT EQUATION IS: MgO(s) + ___ Fe(s) ===> Fe2O3(s) + ___ Mg(s)

The balanced equation is: 3MgO(s) + 2Fe(s) ===> Fe2O3(s) + 3Mg(s)

molar mass of 3MgO = 3(24 + 16) = 120

Molar mass of Fe2O3 = 2 X 56 + 3 X 16

=112 +48 =160

From the equation, 120g of MgO Produced 160g of Fe2O3

Therefore 20g of Fe2O3 will be produced by 20 ×120/160 = 15g of MgO.

7 0

3 years ago