All categories

3 years ago

Write the word and balanced chemical equations for the reaction between:

Chemistry

1 answer:

nadezda [96]3 years ago

3 0

Answer:

3 HNO₃ + Fe(OH)₃ → H₂O + Fe(NO₃)₃

Explanation:

An acid reacts with a base producing water and a salt. Having this in mind the reaction of nitric acid (HNO₃) and Iron (III) hydroxide (Fe(OH)₃) is:

HNO₃ + Fe(OH)₃ → H₂O + Fe(NO₃)₃

<em>The H⁺ of the acid reacts with the OH⁻ to produce H₂O. The other ions (Fe³⁺ and NO₃⁻) produce the salt</em>

<em />

There are 3 nitrates in products. To balance the nitrates:

<em>And this is the balanced reaction</em>

<em />

You might be interested in

The most common element in the atmosphere are

Ivanshal [37]

Nitrogen and oxygen are the most prevalent in the atmosphere.

8 0

3 years ago

Is this an oxidation reaction? Why or why not?

murzikaleks [220]

The oxidation state of Hydrogen in reactant side is 0 and that in product side is +1. Hence the reaction is oxidation.

7 0

3 years ago

Which subatomic particle helps identify an elements identify

Sindrei [870]

Answer:

Protons

Explanation:

Protons are the subatomic particle that determines the identity of an element.

8 0

3 years ago

Electrons involved in bonding between atoms are _____.

never [62]

Valence électrons = are electrons in the outermost shell that is responsible for the chemical reactions of the atoms

8 0

3 years ago

Crime scene investigators keep a wide variety of compounds on hand to help with identifying unknown substances they find in the

almond37 [142]

The powder could be acetaminophen, analgesic having chemical formula $C_{17}H_{21}NO_{4}$

<h3>What is an empirical formula?</h3>

A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule.

We are given:

Percentage of C = 67.31 %

Percentage of H = 6.978 %

Percentage of N = 4.617 %

Percentage of O = 21.10 %

Let the mass of the compound be 100 g. So, the percentages given are taken as mass.

Mass of C = 67.31 g

Mass of H = 6.978 g

Mass of N = 4.617 g

Mass of O = 21.10 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of carbon = $\frac{mass}{molar \;mass}$

Moles of carbon = $\frac{67.31g}{12g/mole}$

=5.60 moles

Moles of hydrogen = $\frac{mass}{molar \;mass}$

Moles of hydrogen = $\frac{6.978 g}{1 g/mole}$

=6.978 moles

Moles of nitrogen = $\frac{mass}{molar \;mass}$

Moles of nitrogen = $\frac{4.617 g}{14 g/mole}$

=0.329 moles

Moles of oxygen = $\frac{mass}{molar \;mass}$

Moles of oxygen = $\frac{21.10 g}{16 g/mole}$

=1.31 moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.329 moles.

We get the ratio of C : H : N : O = 17 : 21 : 1 : 4

The empirical formula for the given compound is $C_{17}H_{21}NO_{4}$ .

Learn more about the empirical formula here:

brainly.com/question/14044066

#SPJ1

3 0

2 years ago