Answer:
Explanation:
Ca(In)²⁺ + EDTA → Ca(EDTA)²⁺ + In
We use the volume of EDTA consumed in the titration to <u>calculate the moles of Ca⁺² ions</u>:
- 0.012 L * 0.0600 M *
= 7.20x10⁻⁴ mol Ca⁺²
Now we <u>calculate the molarity</u>:
- 7.20x10⁻⁴ mol Ca⁺² / 0.050 L = 0.0144 M
To calculate in ppm, we <u>use the moles of Ca⁺² and convert to mg of CaCO₃:</u>
- 7.20x10⁻⁴ mol Ca⁺² = 7.20x10⁻⁴ mol CaCO₃
- 7.20x10⁻⁴ mol CaCO₃ * 100g/mol *
= 72 mg CaCO₃
Finally, <u>the concentration in ppm</u> is:
- 72 mg CaCO₃ / 0.050L = 1440 ppm
Mass 1 + %abundance of first isotope + Mass 2 + %abundance of second isotope
/ 100
This is RAM.
Data:
Molar Mass of NaOH = 40 g/mol
Solving: <span>According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules
</span>
1 mol -------------------- 6.02*10²³ molecules
y mol -------------------- 2.70*10²² molecules
6.02*10²³y = 0.270*10²³
Solving: <span>Find the mass value now
</span>
40 g ----------------- 1 mol of NaOH
x g ------------- 0.04 mol of NaOH
Answer:
The mass is 1.6 grams
Explanation:
the answer and explanation is in the picture
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