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Alenkinab [10]
4 years ago
12

molten iron fills a mould, which has a volume of 200 cm cubed. Calculate the volume when the iron cools and solidifies. Molten i

ron has a density of 7.0g/cm cubed. In its solid state, iron has a density of 8.0g/cm cubed.
Physics
2 answers:
Arada [10]4 years ago
5 0

As we know that mass of the iron will remain same in solid state as well as in molten state as per mass conservation theory

Now we can say

m_{initial} = m_{final}

since mass is the product of volume and density so we can say

V_i \rho_i = V_{final}\rho_{final}

now from above equation we have

(200 cm^3)(7 g/cm^3) = V_{final}(8 g/cm^3)

now by solving above equation we have

V_{final} = \frac{7}{8} (200 cm^3)

V_{final} = 175 cm^3

so final volume after it get solidify will become 175 cm^3

Black_prince [1.1K]4 years ago
5 0

Answer:

901 Shelby drive look alive look alive

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katen-ka-za [31]

The initial potential energy of the wagon containing gold boxes will enable

it roll down the hill when cut loose.

The Lone Ranger and Tonto have approximately <u>5.1 seconds</u>.

Reasons:

Mass wagon and gold = 166 kg

Location of the wagon = 77 meters up the hill

Slope of the hill = 8°

Location of the rangers = 41 meters from the canyon

Mass of Lone Ranger, m₁ = 65 kg

Mass of Tonto m₂ = 66 kg

Solution;

Height of the wagon above the level ground, h = 77 m × sin(8°) ≈ 10.72 m

Potential energy = m·g·h

Where;

g = Acceleration due to gravity ≈ 9.81 m/s²

Potential energy of wagon, P.E. ≈ 166 × 9.81 × 10.72 = 17457.0912

Potential energy of wagon, P.E. ≈ 17457.0912 J

By energy conservation, P.E. = K.E.

K.E. = \mathbf{\dfrac{1}{2} \cdot m \cdot v^2}

Where;

v = The velocity of the wagon a the bottom of the cliff

Therefore;

\dfrac{1}{2} \times 166 \times v^2 = 17457.0912

v = \sqrt{\dfrac{17457.0912}{\dfrac{1}{2} \times 166} } \approx 14.5

Velocity of the wagon, v ≈ 14.5 m/s

Momentum = Mass, m × Velocity, v

Initial momentum of wagon = m·v

Final momentum of wagon and ranger = (m + m₁ + m₂)·v'

By conservation of momentum, we have;

m·v = (m + m₁ + m₂)·v'

\therefore v' = \mathbf{ \dfrac{m \cdot v}{(m + m_1 + m_2)  }}

Which gives;

\therefore v' = \dfrac{166 \times 14.5}{(166 + 65 + 66)  } \approx 8.1

The velocity of the wagon after the Ranger and Tonto drop in, v' ≈ 8.1 m/s

Time = \dfrac{Distance}{Velocity}

\mathrm{The \ time \ the\ Lone \  Ranger \  and  \ Tonto \  have,  \ t} = \dfrac{41 \, m}{8.1 \, m/s} \approx 5.1 \, s

The Lone Range and Tonto have approximately <u>5.1 seconds</u> to grab the

gold and jump out of the wagon before the wagon heads over the cliff.

Learn more here:

brainly.com/question/11888124

brainly.com/question/16492221

5 0
2 years ago
Estimate the wavelength of electrons that have been accelerated from rest through a potential difference of 60 kV.
ivolga24 [154]

Answer: 2.068*10^{-14}m

Explanation: According to work energy-theorem , the workdone in accelerating the electron equals the energy it would give off in terms of light.

workdone= qV

energy = hc/λ

q=magnitude of an electronic charge= 1.602*10^{-16}

h= planck constant = 6.626*10^{-34}

c= speed of light =2.998* 10^{8}

v= potential difference= 6*10^{4}

λ= wavelength=unknown

by making λ subject of formulae we have that

λ= \frac{hc}{qv}

λ = 6.626*10^{-34} * 2.998* 10^{8} / 1.602*10^{-16} * 6*10^{4}

λ = \frac{19.878*10^{-26} }{9.612*10^{-12} }

by doing the necessary calculations, we have that

λ = 2.068*10^{-14}m

8 0
3 years ago
The same wave travels for 2 seconds, what is its frequency?*
sveticcg [70]

Answer:

In waves distance is measured by wave length  and time is measured by frequency or period.

velocity ratio=wave length multiply by frequency.

HENCE, if the same wave travels for 2 econds its frequency will be 2Hz.

Explanation:

8 0
3 years ago
How does the diameter of the disk of milky way galaxy compare to its thickness?
weqwewe [10]
The diameter is about 100 times as great as the thickness.
7 0
4 years ago
PLEASE HELP !!
kumpel [21]

Answer:

Movement Time

explanation:

5 0
3 years ago
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