Yes, it's true.
But 2nd Newton Law always come to play when the horse is to move forward because obviously the forces interact antagonistically and mass has to be accounted for.
That's what I think. Hope it's right, all the best.
Answer:
See the explanation
Explanation:
Given:
Distance of Firecrackers A and B = 600 m
Event 1 = firecracker 1 explodes
Event 2 = firecracker 2 explodes
Distance of lab partner from cracker A = 300 m
You observe the explosions at the same time
to find:
does event 1 occur before, after, or at the same time as event 2?
Solution:
Since the lab partner is at 300 m distance from the firecracker A and Firecrackers A and B are 600 m apart
So the distance of fire cracker B from the lab partner is:
600 m + 300 m = 900 m
It takes longer for the light from the more distant firecracker to reach so
Let T1 represents the time taken for light from firecracker A to reach lab partner
T1 = 300/c
It is 300 because lab partner is 300 m on other side of firecracker A
Let T2 represents the time taken for light from firecracker B to reach lab partner
T2 = 900/c
It is 900 because lab partner is 900 m on other side of firecracker B
T2 = T1
900 = 300
900 = 3(300)
T2 = 3(T1)
Hence lab partner observes the explosion of the firecracker A before the explosion of firecracker B.
Since event 1 = firecracker 1 explodes and event 2 = firecracker 2 explodes
So this concludes that lab partner sees event 1 occur first and lab partner is smart enough to correct for the travel time of light and conclude that the events occur at the same time.
After reading this whole question, I feel like I've already
earned 5 points !
-- Two satellites at the same distance, different masses:
The forces of gravity between two objects are directly
proportional to the product of the objects' masses. In
other words, the gravitational forces between the Earth
and an object on its surface are proportional to the mass of
the object. In other words, people with more mass weigh more
on the Earth, and the Earth weighs more on them.
If the satellites are both at the same distance from Earth,
then the Earth pulls on the one with more mass with greater
force, and also the one with more mass pulls on the Earth
with greater force.
-- Two satellites with the same mass, at different distances:
The forces of gravity between two objects are inversely
proportional to the square of the distance between them.
In other words, the gravitational
forces between the Earth
and an object are inversely proportional
to the square of
the distance between the object and the center of the Earth.
If
the satellites both have the same mass, then the Earth
pulls on the nearer one with greater force, and also the
nearer one pulls on the Earth with greater force.
-- Resistor in a circuit when the voltage changes:
The resistance depends on how the resistor was manufactured.
Its resistance is marked on it, and doesn't change. It remains
the same whether the voltage changes, the current changes,
the time of day changes, the cost of oil changes, etc.
If you increase the voltage in the circuit where that resistor is
installed, the current through the resistor increases. If the current
remains constant, then you can be sure that somebody snuck over
to your circuit when you weren't looking, and they either installed
another resistor in series with the original one to make the total
resistance bigger, or else they snipped the original one out of the
circuit and quickly connected one with more resistance in its place.
Answer:
a = 2.94 m/s²
Explanation:
In order for the cup not to slip, the unbalanced force on cup must be equal to the frictional force:
Unbalanced Force = Frictional Force
ma = μR = μW
ma = μmg
a = μg
where,
a = maximum acceleration for the cup not to slip = ?
μ = coefficient of static friction = 0.3
g = acceleration due to gravity = 9.8 m/s²
Therefore,
a = (0.3)(9.8 m/s²)
<u>a = 2.94 m/s²</u>
