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Aleonysh [2.5K]
3 years ago
11

What measures the distance between two consecutive crests of a wave?

Physics
1 answer:
aleksley [76]3 years ago
4 0
The answer is d. Wavelength
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Explain giving an example for;
Bingel [31]

\boxed{\large{\bold{\red{ANSWER~:) }}}}

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6 0
3 years ago
What are the seasonal changes in the weasel in florida and the weasel in wyoming
AlekseyPX
Winter weasels, also called ermines or short-tailed weasels, have coats that turn from light brown to white in the winter. The color change begins at their stomachs and works its way outward, occurring in both spring and fall. Other species, like the long-tailed weasel, may turn at least partially white as well.

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7 0
3 years ago
If there is 8 g of a substance before a physical change , how much will there be afterwards?
Dimas [21]
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8 0
4 years ago
Read 2 more answers
Imagine that the satellite described in the problem introduction is used to transmit television signals. You have a satellite TV
denpristay [2]

Answer:

R₁ = 0.126 m

Explanation:

Let's use the definition of intensity which is the power per unit area

          I = P / A

the generated power is constant

          P = I A

power is

         P = E / t

if we perform the calculations for a given time, the wave energy is

        E = q V

we substitute

        P = \frac{q V\ A}{t}

we can write this equation for two points, point 1 the antenna and point 2 the receiver

         V₁A₁ = V₂A₂

          A₁ = \frac{V_2}{V_1} \ A_2

          A₁ = 0.1 10⁻³  5 10⁻⁴ /V₁

          A₁ = 5 10⁻⁸ /V₁

In general, the electric field on the antenna is very small on the order of micro volts, suppose V₁ = 1 10⁻⁶ V

           

let's calculate

          A₁ = 5 10⁻⁸ / 1 10⁻⁶

         A₁ = 5 10⁻² m²

the area of ​​a circle is

          A = π r²

we substitute

         π R1₁²= 5 10⁻²

         R₁ = \sqrt{    \frac{5 \ 10^{-2} }{\pi } }}

         R₁ = 0.126 m

5 0
3 years ago
If you are driving 100 km/h along a straight road and you look to the side for 1.6 s , how far do you travel during this inatten
denis23 [38]

Answer:

The distance traveled is 44.45 m

Solution:

As per the question:

Average speed, \bar{v} = 100\ km/h

Time, t = 1.6 s

Now, convert the average speed into m/s:

1 km = 1000 m

1 h = 60\times 60 = 3600\ s

To calculate the distance traveled:

Now,

100\ km/h = \frac{100\times 1000}{3600} = 27.78\ m/s

We know that:

Speed, \bar{v} = \frac{distance,\ d}{time,\ t}

Thus

d = \bar{v}t

d = 27.78\times 1.6 = 44.45\ m

8 0
3 years ago
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