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frutty [35]
2 years ago
15

WILL VOTE MOST BRAINLIEST

Physics
1 answer:
andrezito [222]2 years ago
8 0

Answer:

B) The lighter gases boiled off of the protoplanets closest to the sun, leaving dust and metals behind to form the inner planets.

Explanation:

Inner planets are smaller and rockier than outer gas planets,outer planets are larger,because of their lower gravity they don't attract extreme amounts of gas in their planets.The four outer planets were so far from the Sun that its winds could not blow away their ice and gases

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What net force is required to accelerate a car at a rate of 2m/s^2 if the car has a mass of 3,000kg? plus explanation with equat
Vinvika [58]

Answer:

<h2>6000 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

mass = 3000 kg

acceleration = 2 m/s²

We have

force = 3000 × 2 = 6000

We have the final answer as

<h3>6000 N</h3>

Hope this helps you

3 0
2 years ago
HELP ME PLEASEEEEEEEEEEEEEE
cestrela7 [59]

Answer:

u r right

Explanation:

it is A. DNA

i took that class.

:)

6 0
2 years ago
Read 2 more answers
An inquisitive physics student and mountain climber climbs a 54.0-m-high cliff that overhangs a calm pool of water. He throws tw
kvv77 [185]

Answer:

a) After the release of the first stone the two stones hit the water at 3.14 seconds.

b)Initial velocity of second stone = 14.74 m/s

c) Speed of first stone at the instant the two stones hit the water = 32.62 m/s

Speed of second stone at the instant the two stones hit the water = 35.73 m/s

Explanation:

a) For first stone we have

  Initial velocity, u =  1.82 m/s

  Acceleration , a = 9.81 m/s²

  Displacement, s = 54 m

  We have equation of motion s= ut + 0.5 at²

 Substituting

   s= ut + 0.5 at²

    54 = 1.82 x t + 0.5 x 9.81 x t²

    4.905 t² + 1.82 t - 54 = 0

    t = 3.14 s or t = -3.51 s  (not possible)

After the release of the first stone the two stones hit the water at 3.14 seconds.

b) The second stone is thrown after 1 s

 Time taken by second stone to reach top of pool of water = 3.14 - 1 = 2.14 s

  Time, t =  2.14 m/s

  Acceleration , a = 9.81 m/s²

  Displacement, s = 54 m

  We have equation of motion s= ut + 0.5 at²

 Substituting

   s= ut + 0.5 at²

    54 = u x 2.14 + 0.5 x 9.81 x 2.14²

    u = 14.74 m/s

  Initial velocity of second stone = 14.74 m/s

c) We have equation of motion v = u + at

 For first stone

                  Initial velocity, u =  1.82 m/s

                  Acceleration , a = 9.81 m/s²

                  Time, t = 3.14 s

                  v = 1.82 + 9.81 x 3.14 = 32.62 m/s

 For second stone

                  Initial velocity, u =  14.74 m/s

                  Acceleration , a = 9.81 m/s²

                  Time, t = 2.14 s

                  v = 14.74 + 9.81 x 2.14 = 35.73 m/s

Speed of first stone at the instant the two stones hit the water = 32.62 m/s

Speed of second stone at the instant the two stones hit the water = 35.73 m/s

6 0
3 years ago
PLS ANSWER F A S T
Marizza181 [45]
Just so you know people aren’t replying because the bar graph isn’t show :/
7 0
3 years ago
What is the force when an object exerts 15 pascal pressure on a square surface of side 5 meters
Oksana_A [137]

Answer:375N

Explanation:

pressure =15 pascal

Length =5 m

Area=length x length

Area=5 x 5

Area=25 m^2

Force=pressure x area

Force=15 x 25

Force=375N

5 0
3 years ago
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