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3 years ago

WILL VOTE MOST BRAINLIEST

Physics

1 answer:

andrezito [222]3 years ago

8 0

Answer:

B) The lighter gases boiled off of the protoplanets closest to the sun, leaving dust and metals behind to form the inner planets.

Explanation:

Inner planets are smaller and rockier than outer gas planets,outer planets are larger,because of their lower gravity they don't attract extreme amounts of gas in their planets.The four outer planets were so far from the Sun that its winds could not blow away their ice and gases

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State and explain poiseuilles formula<br><br>

Komok [63]

The Poiseuille's Law formula is given by:
The Pressure Gradient (∆P) Shows the pressure differential between the two ends of the tube, defined by the fact that every fluid will always flow from the high pressure (P1) to the low-pressure area (P2) and the flow rate is calculated by the ∆P = P1-P2.

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3 years ago

Atoms move slower in solids than they do in liquids

MakcuM [25]

Solids are just vibrating and they cannot move past each other
the liquids they move freely and move past each other

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4 years ago

A -4.33x10^-6 charge is placed a certain distance from a -7.81x10^-4 C charge. Their electric potential energy is 44.9 J. How fa

KATRIN_1 [288]

Answer:

0.67709

Explanation:

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3 years ago

1. A 1000-kg car moves as speed from 10 m/s to 30 m/s in 20 seconds. What is the average speed? What is the acceleration? What i

kaheart [24]

Explanation:

Given parameters:

Mass of car = 1000kg

initial speed = 10m/s

final speed = 30m/s

time taken = 20s

For centripetal force:

velocity = 5m/s

radius = 30m

Unknown:

Average speed = ?

Acceleration = ?

Average force = ?

Centripetal force = ?

Solution:

Average speed is the rate of change of distance with time.

In this problem, we were given two speeds and we will simply just find their average. We sum them up and divide by 2

Average speed = $\frac{initial speed + final speed }{2}$

Average speed = $\frac{10 + 30}{2}$ = 20m/s

Acceleration is the change in the velocity or speed of a body with time.

Acceleration = $\frac{final speed - initial speed }{time}$

Acceleration = $\frac{30 - 10}{20}$ = 1m/s²

Average force on the car is the product of its mass and acceleration:

Acceleration = mass x acceleration

Acceleration = 1000 x 1 = 1000N

Centripetal force is the inward pull when a body moves round a fixed center.

It is given as:

F = $\frac{mv^{2} }{r}$

m is the mass of the body

v is the velocity

r is the radius

input the parameters:

F = $\frac{1000 x 5^{2} }{30}$ = 833.3N

learn more:

Acceleration brainly.com/question/11025333

Motion brainly.com/question/2863017

#learnwithBrainly

6 0

4 years ago

1.A steel cable is attached to a ring on the top of a street light. The weight of the street light is W . The other end of the c

mixer [17]

Answer:

a) Please find attached, the vector diagram regarding the question

i) The direction of the sum of the vectors is the negative direction of the vertical or y-axis

ii) The scale is 1 mm = 1 N

W = 25 N

The mass of W is approximately 2.55 kg

Explanation:

The given parameters are;

The angle of inclination of the cable to the vertical = 55°

The tension in the cable = 43.6 N

a) i) The direction of the vector sum of the two forces is given as the resultant of the two forces;

The component of the tension in the chain is given as follows;

Tension in the horizontal chain = x $\mathbf{ \hat i}$

The resolved force in the cable is given as follows;

Given that the force is acting upwards along the cable

F = 43.6 × -sin(55°) $\mathbf{ \hat i}$ + 43.6 × cos(55°) $\mathbf{ \hat j}$

F ≈ -35.72 $\mathbf{ \hat i}$ + 25 $\mathbf{ \hat j}$

Therefore, from ∑Fₓ = 0 and ∑F $_y$ = 0, since the horizontal force in the chain will balance the horizontal component of the tension in the cable, there will be no net horizontal force and the resultant force will have a direction of the vertical y-axis

ii)

Given that ∑F = 0, we have;

The tension in the cable is an horizontal force, therefore, we have;

∑Fₓ = 0

The tension in the horizontal chain + The horizontal component of the cable = 0

The tension in the horizontal chain - 35.72 N = 0

∴ The tension in the horizontal chain = 35.72 N

The weight of the street light + The vertical component of the tension = 0

The weight of the street light + 25 N = 0

Therefore;

The weight of the street light W = -25 N

The scale of the vector diagram used is <u>1 mm = 1 N</u>

W = -25 N

The mass of the street light = Weight of the street light/(Acceleration due to gravity)

The mass of the street light = 25 N/(9.81 m/s²) ≈ 2.55 kg

7 0

3 years ago