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alisha [4.7K]
3 years ago
13

Define monosaccharide disaccharide and polysaccharide give at least two examples of each. which of these is the

Chemistry
1 answer:
Ainat [17]3 years ago
6 0
Saccharides are carbohydrates, molecules containing Carbon (C), Hydrogen (H), and Oxygen (O). "Saccharo" means sugar in Greek. Also Greek, "mono" means one, "di" means two, and "poly" means many.
A sugar molecule is based upon a ring of carbons with H's and OH's attached. One sugar molecule alone is a monosacchararide, like glucose and fructose. Two sugar molecules bonded together covalently is a disaccharide, like lactose (milk sugar) and sucrose (table sugar). Many sugar molecules (upwards of hundreds or thousands) bonded together covalently is a polysaccharide. Examples are glycogen (animal starch) and cellulose (plant starch).
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You're provided with a bottle labled [CoCl2.6H2O] = 0.056 M in 4.60 M HCl. You heat a small volume of the solution in a hot wate
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Answer: Equilibrium concentration of [Cl^-] at 50^0C is 4.538 M

Explanation:

Initial concentration of CoCl_2 = 0.056 M

Initial concentration of Cl^- = 4.60 M

The given balanced equilibrium reaction is,

               COCl_2+2Cl^-\rightleftharpoons [CoCl_4]^{2-}+6H_2O

Initial conc.          0.056 M      4.60 M        0 M       0 M

At eqm. conc.     (0.056-x) M   (4.60-2x) M   (x) M    (6x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CoCl_4]^{2-}\times [H_2O]^6}{[CoCl_2]^2\times [Cl^-]^2}

Given : equilibrium concentration of [CoCl_4]^{2-} =x =  0.031 M

Concentration of Cl^- = (4.60-2x) M  = (4.60-2\times 0.031) =4.538 M  

Thus equilibrium concentration of [Cl^-] at 50^0C is 4.538 M

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