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olga nikolaevna [1]
3 years ago
14

Why do you think evolution is important?

Chemistry
2 answers:
Andrew [12]3 years ago
6 0
Evolution isn’t god is
enot [183]3 years ago
4 0
Understanding evolution is important. Understanding evolution helps us solve biological problems that impact our lives. ... To control hereditary diseases in people, researchers study the evolutionary histories of the disease-causing genes. In these ways, a knowledge of evolution can improve the quality of human life!
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The p-value of a statistical test depends on all of the following, except:
vaieri [72.5K]

Answer:

The correct option is e.

Explanation:

p-value is the probability value for a given statistical model, the probability that, when the null hypothesis is true.

For two two samples the formula of test statistics is

t=\frac{(\overline{x}_1-\overline{x}_2)-(\mu_1-\mu_2)}{\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}}

where,

\overline{x} is sample mean

\mu is population mean.

s is standard deviation.

n is sample size.

Variance is the square of standard deviation.

It means variance, mean, numbers of samples is used in calculation of p-value.

Degree of freedom define the shape of the t-distribution that your t-test uses to calculate the p-value.

d.f.=n_1+n_2-2

p-value of a statistical test depends on all of the following, except median.

Therefore the correct option is e.

4 0
3 years ago
What is the mass of OH- in Ca(OH)2
Ne4ueva [31]
Oxygen: 16.00 g/mol
Hydrogen: 1.01 g/mol

The mass would be 17.01 g/mol
5 0
3 years ago
Gaseous methane (CH4) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO) and gaseous water (H2O) . Suppo
Leto [7]

Answer:

0 g.

Explanation:

Hello,

In this case, since the reaction between methane and oxygen is:

CH_4+2O_2\rightarrow CO_2+2H_2O

If 0.963 g of methane react with 7.5 g of oxygen the first step is to identify the limiting reactant for which we compute the available moles of methane and the moles of methane consumed by the 7.5 g of oxygen:

n_{CH_4}=0.963gCH_4*\frac{1molCH_4}{16gCH_4}=0.0602molCH_4\\ \\n_{CH_4}^{consumed}=7.5gO_2*\frac{1molO_2}{32gO_2}*\frac{1molCH_4}{2molO_2} =0.117molCH_4

Thus, since oxygen theoretically consumes more methane than the available, we conclude the methane is the limiting reactant, for which it will be completely consumed, therefore, no remaining methane will be left over.

left\ over=0g

Regards.

7 0
3 years ago
74.5 g of KCl was dissolved in 1000. mL of water. What is the
Degger [83]
Hdhdhdhxhxuxbxuxbdhudhx
3 0
3 years ago
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Please help<br> Will give brainliest<br> A - 1<br> B - 2<br> C - 3<br> D - 4<br> E - 5
Basile [38]

Answer:

B-2

Explanation:

In the graph you can so that two of the shapes ae fully black, that means that they are color blind, the half colored ones means they are a carrier but they aren't color blind. So two males in the offspring are color blind.

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3 years ago
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