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Harman [31]
4 years ago
9

Kevin is standing outside a railway station. He can know whether a train is approaching the station or departing from the sound

it makes. Which principle of sound waves is he using? resonance beats Doppler effect interference
Physics
1 answer:
blsea [12.9K]4 years ago
7 0
If Kevin is good, really good, he can use the principle of the
Doppler effect to distinguish the sound of an approaching train
from the sound of a departing train.

-- The sound of a train APPROACHING the station will have a HIGHER
pitch than the sound actually emitted by the train.

-- The sound of a train moving AWAY from the station will have a LOWER
pitch than the sound actually emitted by the train.

But the skill that Kevin will need is to exactly know the sound actually
emitted by the train ... without hearing it ... and to be able to compare
that to the sound that he DOES hear at the moment.  Not easy. 
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A satellite in geostationary orbit is used to transmit data via electromagnetic radiation. The satellite is at a height of 35,00
Rus_ich [418]

Answer:

6.99535\times 10^{-6}\ V/m

Explanation:

P = Power Output = 1000 W

r = Radius = 35000000 m

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

c = Speed of light = 3\times 10^8\ m/s

Intensity of Electric radiation

I=\frac{P}{A}\\\Rightarrow I=\frac{P}{4\pi r^2}\\\Rightarrow I=\frac{1000}{4\pi\times 35000000^2}\ W/m^2

Intensity of Electric radiation

I=\frac{1}{2}c\epsilon_0E_0\\\Rightarrow E_0=\sqrt{\frac{2I}{c\epsilon_0}}\\\Rightarrow E_0=\sqrt{\frac{2\times \frac{1000}{4\pi\times 35000000^2}}{3\times 10^8\times 8.85\times 10^{-12}}}\\\Rightarrow E_0=6.99535\times 10^{-6}\ V/m

The amplitude of the electric field vector is 6.99535\times 10^{-6}\ V/m

7 0
4 years ago
A few years ago, an X-ray telescope detected a source called Cygnus X-3, whose intensity changed with a period of 4.8 hours. Thi
alina1380 [7]

Answer:

Explanation:

The star is revolving the black hole like earth revolves around the sun .so time period of rotation  T is given by the following relation

T² = \frac{4\pi^2\times R^3}{GM } , R is distance between black hole and star , M is mass of black hole

Given T = 4.8 hours

4.8² =  \frac{4\pi^2\times R^3}{GM }

Using the same equation for earth sun system

24² =  \frac{4\pi^2\times (50R)^3}{GM_s }  , Ms is mass of the sun and 50R is distance between the sun and the earth .

Dividing the equation

(\frac{4.8}{24})^2 = \frac{M_s}{M}\times\frac{1^3}{50^3}

\frac{M}{M_s} = 2x 10⁻⁴

7 0
3 years ago
When a warm air mass collides with a cold air mass, the warm air mass rises above the cold air mass leading too:
nikdorinn [45]

Answer: It leads to a front. A front is.., I don't know how to explain it, so I'll add a picture. Fronts are made out of clouds and usually bring rain. So the answer is C: The formation of clouds and rain.

Explanation:

7 0
3 years ago
A block (mass m1) lying on a frictionless inclined plane is connected to a mass (mass m2) by a massless cord passing over a pull
azamat

Answer:

a) System aceleration:

  • a=\frac{g(m_2-m_1sin(\theta))}{m_1+m_2}

b) Direction of movement:

The block m_1 down the plane when the acceleration is negative. This occur when:

m_2-m_1sin(\theta)

The block m_2 up the plane when the acceleration is positive. This occur when:

m_2-m_1sin(\theta)>0

Explanation:

For the block m_1 the move direction is parallel (||) to the plane

\sum F_{||}=m_1a=T-sin(\theta)mg  (1)

For the block m_2  the move direction is vertical (y)

\sum F_y=m_2a=m_2g-T  (2)

Both blocks are connected with the same cable, therefore, the tension on the cable and the acceleration is the same for both.

Solving the equation 2 for T:

T=m_2g-m_2a   (3)

replacing (3) in the equation (1)

m_2g-m_2a- m_1gsin(\theta)=m_1a  (4)

solving (4) for a:

a=\frac{g(m_2-m_1sin(\theta))}{m_1+m_2}

8 0
3 years ago
Are electric files lines due to an isolated positive point charge emanate radially away from the charge?
lara31 [8.8K]

Answer:

6

Explanation:

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