Answer:
Explanation:
If a small piece of Styrofoam packing material is dropped from a height of 1.90 m above the ground and reaches a terminal speed after falling 0.400m, the Change in distance will be 1.90m - 0.400 = 1.50m
If it takes 5.4secs fo r the Styrofoam to reach the ground, the terminal velocity will be expressed as;
Vt = change in distance/time
Vt = 1.5m/5.4s
Vt = 0.28m/s
Note that the Styrofoam reaches its final velocity when the acceleration is zero.
To get the constant value B from the equation a = g-Bv
a = 0m/s²
g = 9.81m/s²
v = 0.28m/s
Substituting the parameters into the formula.
0 = 9.81-0.28B
-9.81 = -0.28B
Divide both sides by -0.28
B = -9.81/-0.28
B = 35.04
b) at t = 0sec, the initial terminal velocity is also zero.
Substituting v = 0 into the equation to get the acceleration.
a = g-Bv
a = g-B(0)
a = g
Hence the acceleration at t =0s is equal to the acceleration due to gravity which is 9.81m/s²
c) Given speed v = 0.150m/s
g = 9.81m/s²
B = 35.04
Substituting the given data into the equation a = g-Bv
a = 9.81-35.04(0.15)
a = 9.81 - 5.26
a = 4.55m/s²
Answer:
distance travelled
Explanation:
the area under a speed time graph represents distance travelled because speed is the distance divided by time
Ok the velocity of an object in free fall is given by the equation :
v=v0-gt, where v0 is the original velocity, g is the gravitational constant (9.8 m/s^2) and t is the time.
so, we substitute values into this equation. v=35.8-9.8*2.5; v=11.3 m/s
