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Margaret [11]
3 years ago
12

Describe a way that someone could estimate a length of a book

Mathematics
1 answer:
o-na [289]3 years ago
8 0
Look at the height and width of the book
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PLEASE PLEASE HELP!!!!
Usimov [2.4K]

Answer:

B

Step-by-step explanation:

\cos( \alpha )  +  i\sin( \alpha )  =  {e}^{i (\alpha   + 2\pi)}

z = 3(cos π/2 + i sin π/2) =→

3 {e}^{i \frac{\pi}{2} }

z⁷ =

{3}^{7}  {e}^{i \frac{7\pi}{2} }  =   {3}^{7}  {e}^{i \frac{(7 - 4)\pi}{2} }  =  {3}^{7}  {e}^{i \frac{3\pi}{2} }  =  {3}^{7} ( \cos( \frac{3\pi}{2} )  + i \sin( \frac{3\pi}{2} ) ) = 2187( \cos( \frac{3\pi}{2} )  + i \sin( \frac{3\pi}{2} ) )

6 0
2 years ago
Shley solved the exponential equation 3x+1 = 15 and her work is shown below. what is the first step she did incorrectly? step 1:
HACTEHA [7]
The step 2 because 3 is not multiplying the 1 only the x in the bracket
7 0
3 years ago
Find the value of x in 4:6=x:3​
frozen [14]

Answer:

x = 2

Step-by-step explanation:

Express the ratio in fractional form

\frac{4}{6} = \frac{x}{3} ( cross- multiply )

6x = 12 ( divide both sides by 6 )

x = 2

4 0
3 years ago
Write a story that could represent this math problem.
defon

Answer:

oNE DAY A TRIANGLE SPLIT IN SO MANY DIFFERENT PEICES VBUT SUDDENLY ONE DAY THEY ALL CAME BACK.....

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
5. Write down the nth term of each of the following G.Ps
yawa3891 [41]

Answer:

1i) nth term = 12(-b/4)^(n-1)

ii) nth term = 3(-1/9)^(n-1)

2i) Sixth term= (-3b^5)/256

ii) Eight term = -1/1594323

Question:

The complete question as found on brainly (question-10746111):

Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.

i) 12,-3b,......sixth term

ii) 3,-1/3,..........;8th term?

Step-by-step explanation:

1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.

i) 12,-3b,......;sixth term

1st term = a= 12

r = common ratio = 2nd term /1st term

r = -3b/12 = -b/4

Then we would find the nth term

See attachment for details

ii) 3,-1/3,..........;8th term

1st term = a= 3

r = common ratio = 2nd term /1st term

r = (-⅓)/3 = (-⅓)(⅓) = -1/9

Then we would find the nth term

See attachment for details

2) we are to determine the sixth term in (i) and eight term in (ii)

See attachment for details

Sixth term= (-3b^5)/256

Eight term = -1/1594323

7 0
3 years ago
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