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3 years ago

12

Describe a way that someone could estimate a length of a book

1 answer:

o-na [289]3 years ago

8 0

Look at the height and width of the book

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Sladkaya [172]

Answer:

Step-by-step explanation:

The answer is d.

6 0

3 years ago

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Plato combining functions mastery test please help

just olya [345]

Answer:

<em>Choice: B.</em>

Step-by-step explanation:

<u>Operations With Functions</u>

Given the functions:

$f(x)=\sqrt[3]{12x+1}+4$

$g(x)=\log(x-3)+6$

The function (g-f)(x) can be obtained by replacing both functions and subtracting them as follows:

$(g-f)(x)= g(x) - f(x)$

$(g-f)(x)= \log(x-3)+6 - (\sqrt[3]{12x+1}+4)$

Operating:

$(g-f)(x)= \log(x-3)+6 - \sqrt[3]{12x+1}-4$

Joining like terms:

$\boxed{(g-f)(x)= \log(x-3) - \sqrt[3]{12x+1}+2}$

Choice: B.

7 0

3 years ago

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Give the properties for the equation -2x 2 - y + 10x - 7 = 0.

Sladkaya [172]

Given:

The quadratic equation is

$-2x^2-y+10x-7=0$

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

We have,

$-2x^2-y+10x-7=0$

It can be written as

$-2x^2+10x-7=y$

$y=-2x^2+10x-7$ ...(i)

Here, $a=-2,b=10,c=-7$ .

$\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}$

$\dfrac{-b}{2a}=\dfrac{-10}{-4}$

$\dfrac{-b}{2a}=\dfrac{5}{2}$

Putting $x=\dfrac{5}{2}$ in (i), we get

$y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7$

$y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7$

$y=\dfrac{-50}{4}+25-7$

$y=\dfrac{-25}{2}+18$

On further simplification, we get

$y=\dfrac{-25+36}{2}$

$y=\dfrac{11}{2}$

So, the vertex of the given quadratic equation is $\left(\dfrac{5}{2},\dfrac{11}{2}\right)$ .

Therefore, the correct option is A.

3 0

3 years ago

What equation represents the line that passes through points (1.-5) and (3 -17)?

zzz [600]

ALL LINES CAN BE REPRESENTED IN THE FORM $f(x) = ax+b$ .

We know that:

$f(1) = -5 \implies a\cdot(1)+b = -5 \implies a+b = -5$

and

$f(3) = -17 \implies a\cdot(3) +b = -17 \implies 3a+b = 17$

Observe that:

$3a+b = 2a+a+b = 2a+(a+b)$

So:

$2a+(a+b) =-17$

But we know that $a+b = -5$ , so:

$2a+(a+b) =-17$

$2a+(-5) = -17$

$2a = -12$

$a = -6$

Since:

$a+b = -5$

$(-6)+b = -5$

$b = 1$

So the line is:

$f(x) = 1-6x$

5 0

3 years ago

Chose the triangle that seems congruent to the given one

Tems11 [23]

I think the answer is: ACD

4 0

3 years ago

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