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2 years ago

Boron occurs naturally as two isotopes. What is the difference between these isotopes?

2 answers:

Citrus2011 [14]2 years ago

6 0

"They have different numbers of neutrons and different mass numbers. Remember mass number is protons plus neutrons. The number of protons for an element will never change, however the number of neutrons can." I took the test, its D

Oksanka [162]2 years ago

4 0

Answer: The two isotopes of boron differs in mass number rather than atomic number.

Explanation:

Isotopes are defined as the chemical species that have same atomic number but differ in their mass number.

Boron is the 5th element of the periodic table and have 2 naturally occurring isotopes. The isotopes are : B-10 and B-11

For $_5^{10}\textrm{B}$ isotope:

Percentage abundance of this isotope = 20 %

Atomic number = 5

Mass number = 10

For $_5^{11}\textrm{B}$ isotope:

Percentage abundance of this isotope = 80 %

Atomic number = 5

Mass number = 11

Hence, the two isotopes of boron differs in mass number rather than atomic number.

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How do we turn petroleum into energy we use?

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You don't "turn" it into energy; petroleum HAS stored energy (chemical energy).However, you can turn it into ANOTHER TYPE OF ENERGY; usually this is done by burning the petroleum, and using it to drive machinery.

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3 years ago

Consider the reactionI2(g) + Cl2(g)2ICl(g)Using standard thermodynamic data at 298K, calculate the entropy change for the surrou

Georgia [21]

We know,

$\Delta H_{I_2(g)}=62.438\ KJ/mol\\\\\Delta H_{Cl_2(g)}= 0.0\ KJ/mol\\\\\Delta H_{ICl(g)}=17.78\ KJ/mol$

For given reaction, $I_2(g)+Cl_2(g)\ -->\ 2ICl(g)$

$\Delta H_{rxn}=2\Delta H_{ICl(g)}-\Delta H_{I_2(g)}-\Delta H_{Cl_2(g)}\\\\\Delta H_{rxn}=2(17.78)-0-62.438\ KJ/mol\\\\\Delta H_{rxn}=-26.878\ KJ/mol$

For , 2.41 moles of $I_2$ :

$\Delta H_{rxn}=2.41\times (-26.878)\ KJ\\\\\Delta H_{rxn}=-64.78\ KJ$

We know :

$\Delta S = -\dfrac{\Delta H_{rxn}}{T}\\\\\Delta S = -\dfrac{-64.78}{298}\ KJ/K\\\\\Delta S =-0.21738 \ KJ/K\\\\\Delta S=-217.38\ J/K$

Hence, this is the required solution.

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3 years ago

What are three applications of the coal

labwork [276]

Three uses of coal:

1. Electricity generation

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Hope it helps!

3 0

2 years ago

The pressure exerted by 1.5 mol of gas in a 13 L flask at 22 °C is ____ kPa

sukhopar [10]

Answer:

282.7KPa

Explanation:

Step 1:

Data obtained from the question.

Number of mole of (n) = 1.5 mole

Volume (V) = 13L

Temperature (T) = 22°C = 22 + 273°C = 295K

Pressure (P) =..?

Gas constant (R) = 0.082atm.L/Kmol

Step 2:

Determination of the pressure exerted by the gas.

This can be obtained by using the ideal gas equation as follow:

PV = nRT

P = nRT /V

P = 1.5 x 0.082 x 295 / 13

P = 2.79atm.

Step 3:

Conversion of 2.79atm to KPa.

This is illustrated below:

1 atm = 101.325KPa

Therefore, 2.79atm = 2.79 x 101.325 = 282.7KPa

Therefore, the pressure exerted by the gas in KPa is 282.7KPa

8 0

2 years ago