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DaniilM [7]
3 years ago
10

Boron occurs naturally as two isotopes. What is the difference between these isotopes?

Chemistry
2 answers:
Citrus2011 [14]3 years ago
6 0
<span>"They have different numbers of neutrons and different mass numbers.  Remember mass number is protons plus neutrons. The number of protons for an element will never change, however the number of neutrons can." I took the test, its D</span>
Oksanka [162]3 years ago
4 0

<u>Answer:</u> The two isotopes of boron differs in mass number rather than atomic number.

<u>Explanation:</u>

Isotopes are defined as the chemical species that have same atomic number but differ in their mass number.

Boron is the 5th element of the periodic table and have 2 naturally occurring isotopes. The isotopes are : B-10 and B-11

<u>For _5^{10}\textrm{B} isotope:</u>

Percentage abundance of this isotope = 20 %

Atomic number = 5

Mass number = 10

<u>For _5^{11}\textrm{B} isotope:</u>

Percentage abundance of this isotope = 80 %

Atomic number = 5

Mass number = 11

Hence, the two isotopes of boron differs in mass number rather than atomic number.

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Answer:  hello the complete question is attached below

Visibility of molecular ion = m/z value of 77

Explanation:

For The molecular ion to be visible, it has to be at an m/z value of 77 and this is because molecular ions will have an m/z ratio =  molecular mass of given molecule in most cases but not always in all cases.

And the visibility is possible after the removal of CH₃ ion.

ii) Evidence in the mass spectrum that suggests peak at m/z = 77

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How many total electrons can there be in the n=4 orbital?
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Short Response
Natalija [7]

Answer:

6.)

7.)  134.4 g O₂

Explanation:

The unbalanced equation:

NH₃ (g) + O₂ (g) ---> N₂ (g) + H₂O (g) + energy

<u>Reactants</u>: 1 nitrogen, 3 hydrogen, 2 oxygen

<u>Products</u>: 2 nitrogen, 2 hydrogen, 1 oxygen

The balanced equation:

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<u>Reactants</u>: 4 nitrogen, 12 hydrogen, 6 oxygen

<u>Products</u>: 4 nitrogen, 12 hydrogen, 6 oxygen

To convert from moles to grams, you need to multiply the starting value (4.2 moles) by the molar mass (32.00 g/mol). The molar mass can serve as a conversion because it technically means there are 32.00 grams O₂ per every 1 mole. It is important to arrange this ratio in a way that allows for the cancellation of units (the desired unit should be in the numerator).

4.2 moles O₂          32.00 g
--------------------  x  ----------------  =  134.4 g O₂
                                1 mole

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