Density (p) is defined as the mass (m) per unit volume (v) or:
p = m/v
Using this relationship, the volume is:
v = m/p
Using the given values of mass of 80 grams and density of 8 g/cm3, the sample volume is:
v = 80 grams/8 grams/cm3
v = 10 cm3
The final answer is 10 cm3.
Balanced chemical equation for the given reaction is Fe₂(CO₃)₃ + 6Cs → 3Cs₂CO₃ + 2Fe.
<h3>What is balanced equation?</h3>
Balanced chemical equations are those equations in which all entities are present in equal amount on reactant side as well as on product side.
Given balanced chemical reaction is:
Fe₂(CO₃)₃ + 6Cs → 3Cs₂CO₃ + 2Fe
Above given equation is a balanced chemical equation where all atoms of reactant as well as of products are present in same amount.
Hence, required balanced equation is Fe₂(CO₃)₃ + 6Cs → 3Cs₂CO₃ + 2Fe.
To know more about balanced chemical reaction, visit the below link:
brainly.com/question/26694427
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When products form in an exergonic reaction, the <span>energy required to break bonds is less than the energy released from new bonds. This is usually given off as light. I hope this is the answer you are looking for. Looking forward to help you again. Have a great day ahead!</span>
Answer:
V2~0.4839M
Explanation:
We're going to use Boyles law to answer the question.
Boyle's law:
P1V1=P2V2
P1=151mmHg
P2=166mmHg
V1=0.532L
V2=?
V2=(P1 x V1)/P2
V2=(151 x 0.532)/166
V2~0.4839M
Hope it helps:)
Answer:
Equilibrium shifts to produce more reactant
Explanation:
- <em>Le Châtelier's principle</em> <em>states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>
- When more product is added to the solution:
<em>This will increase the concentration of the products side, so the reaction will be shifted to the lift side (reactants side) to suppress the increase in the concentration of Products.</em>
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<em>So, the right choice is: Equilibrium shifts to produce more reactant</em>