4 years ago

How do you do work and power

Physics

1 answer:

dybincka [34]4 years ago

4 0

Power is the work divided by time

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Two sound waves of equal amplitude interference so that compression of one wave falls on the rarefaction of the other. Which sta

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<span>A. No sound is heard
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3 years ago

3 A jet plane accelerated along a straight runway from rest to a

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Explanation:

v=140 m/s

t=50s

u=0

change of velocity = v-u

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for acceleration:

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140=0+a50

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4 years ago

7. Water flows trough a horizontal tube of diameter 2.5 cm that is joined to a second horizontal tube of diameter 1.2 cm. The pr

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To solve this problem it is necessary to apply the concepts related to the continuity of fluids in a pipeline and apply Bernoulli's balance on the given speeds.

Our values are given as

$d_1 = 2.5cm \rightarrow r_1=1.25cm=1.25*10^{-2}m$

$d_2 = 1.2cm \rightarrow r_2 = 0.6cm = 0.6*10^{-2}m$

From the continuity equations in pipes we have to

$A_1V_1 = A_2 V_2$

Where,

$A_{1,2}$ = Cross sectional Area at each section

$V_{1,2}$ = Flow Velocity at each section

Then replacing we have,

$(\pi r_1^2) v_1 = (\pi r_2^2) v_2$

$(1.25*10^{-2})^2 v_1 = ( 0.06*10^{-2})^2 v_2$

$v_2 = \frac{(1.25*10^{-2})^2 }{0.6*10^{-2})^2} v_1$

From Bernoulli equation we have that the change in the pressure is

$\Delta P = \frac{1}{2} \rho (v_2^2-v_1^2)$

$7.3*10^3 = \frac{1}{2} (1000)([ \frac{(1.25*10^{-2})^2 }{0.6*10^{-2})^2} v_1 ]^2-v_1^2)$

$7300= 8919.01 v_1^2$

$v_1 = 0.9m/s$

Therefore the speed of flow in the first tube is 0.9m/s

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4 years ago

How does sound travel through a medium?

Papessa [141]

Particles vibrate parallel to the direction the sound travels. It's a longitudinal wave.

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3 years ago

Read 2 more answers