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Sladkaya [172]
3 years ago
6

What is the behavior that takes place when two waves of equal amplitude collide abd sum up to a bigger wave.

Physics
1 answer:
olga nikolaevna [1]3 years ago
3 0

That's "constructive interference".

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A box slides down a 31° ramp with an acceleration of 0.99 m/s2. Determine the coefficient of kinetic friction between the box an
tino4ka555 [31]

Answer:\mu=0.48

Explanation:

Given

inclination \theta =31^{\circ}

Acceleration of object=0.99 m/s^2

Now using FBD

mg\sin \theta -f_r=ma

mg\sin \theta -\mu mg\cos \theta =ma

a=g\sin \theta -\mu g\cos \theta

0.99=5.04-\mu 8.4

\mu 8.4=4.057

\mu =0.48

7 0
3 years ago
What is solar power good for?
san4es73 [151]

Answer: the earth

Explanation: ask your teacher

3 0
2 years ago
Read 2 more answers
A small block on a frictionless, horizontal surface has a mass of 0.0250 kg. It is attached to a massless cord passing through a
frosja888 [35]

Answer:

a) Yes

b) 7 rad/s

c) 0.01034 J

Explanation:

a)

Yes the angular momentum of the block is conserved since the net torque on the block is zero.

b)

m = mass of the block = 0.0250 kg

w₀ = initial angular speed before puling the cord = 1.75 rad/s

r₀ = initial radius before puling the cord = 0.3 m

w = final angular speed after puling the cord = ?

r = final  radius after puling the cord = 0.15 m

Using conservation of angular momentum

m r₀² w₀ = m r² w

r₀² w₀ = r² w

(0.3)² (1.75) = (0.15)² w

w = 7 rad/s

c)

Change in kinetic energy is given as

ΔKE = (0.5) (m r² w² - m r₀² w₀²)

ΔKE = (0.5) ((0.025) (0.15)² (7)² - (0.025) (0.3)² (1.75)²)

ΔKE = 0.01034 J

6 0
3 years ago
Kelly sits on a rock. Her weight is an action force. What is the reaction force?
Dmitrij [34]
The force ffrom the ground that holds the rock up and prevents her from falling through the gound, unless the ground breaks.
4 0
4 years ago
A boy is swinging a yo-yo with mass 0.25 kg in a circle with radius 1 m at a speed of 6 m/s. What is the tension in the string c
Paladinen [302]

Answer:

D. 9 N

Explanation:

The tension on the string is equivalent to the centripetal force.

Centripetal force is the force exerted by an object in circular motion or path towards the center of the circular path.

Centripetal force = mv²/r

where m is the mass of the object, v is the velocity and r is the radius of the circular path.

Centripetal force = (0.25 kg × 6²)/ 1

                            = 9 N

Thus, the tension on the string is 9 N

5 0
3 years ago
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