Answer:
N = 148.10N
Explanation:
GIVEN
Weight =125 N
force = 35
angle =42°
since there is no vertical acceleration from
free body diagram
A uniform ladder 5.0 m long rests against a frictionless, vertical wall with its lower end 3.0 m from the wall. The ladder weigh
1 answer:
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The velocity of the pitcher is <u>0.105 m/s</u> in a direction opposite to the velocity of the ball.
When no external force acts on a system, the total momentum of the system is conserved. The total initial momentum of the system is equal to the total final momentum of the system.
The pitcher and the ball are initially at rest, therefore, the total initial momentum of the system is zero.
Since no external forces act on the system comprising of pitcher and the ball, the total final momentum of the system is also equal to zero.
If the mass of the pitcher is mp and its speed is vp, the mass of the ball is mb and the ball's speed is vb, then the final momentum of the system of pitcher and the ball is given by,
Therefore,
Substituet 0.15 kg for mb, 50 kg for mp and 35 m/s for vb.
The pitcher has a velocity <u> 0.105 m/s</u> opposite to the direction of the velocity of the ball.
Answer:
v₂ = 0.56 m / s
Explanation:
This exercise can be done using Bernoulli's equation
P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂
Where points 1 and 2 are on the surface of the glass and the top of the straw
The pressure at the two points is the same because they are open to the atmosphere, if we assume that the surface of the vessel is much sea that the area of the straw the velocity of the surface of the vessel is almost zero v₁ = 0
The difference in height between the level of the glass and the straw is constant and equal to 1.6 cm = 1.6 10⁻² m
We substitute in the equation
+ ρ g y₁ =
+ ½ ρ v₂² + ρ g y₂
½ v₂² = g (y₂-y₁)
v₂ = √ 2 g (y₂-y₁)
Let's calculate
v₂ = √ (2 9.8 1.6 10⁻²)
v₂ = 0.56 m / s