Explanation:
Given that,
Radius of circular path, r = 5 m
Centripetal acceleration, 
(a) Let v is the astronaut’s speed. The formula for the centripetal acceleration is given by :
v = 18.5 m/s
(b) Let T denotes the time period. It is given by :
T = 1.69 s
Let N is the number of revolutions. So,
So, the number of revolutions per minute is 35.5
(c) T = 1.69 seconds
Hence, this is the required solution.
<span>Phase, color, and ductility are all examples of physical external properties</span>
Answer:
The position of the particle is -2.34 m.
Explanation:
Hi there!
The equation of position of a particle moving in a straight line with constant acceleration is the following:
x = x0 + v0 · t + 1/2 · a · t²
Where:
x = position of the particle at a time t:
x0 = initial position.
v0 = initial velocity.
t = time
a = acceleration
We have the following information:
x0 = 0.270 m
v0 = 0.140 m/s
a = -0.320 m/s²
t = 4.50 s (In the question, where it says "4.50 m/s^2" it should say "4.50 s". I have looked on the web and have confirmed it).
Then, we have all the needed data to calculate the position of the particle:
x = x0 + v0 · t + 1/2 · a · t²
x = 0.270 m + 0.140 m/s · 4.50 s - 1/2 · 0.320 m/s² · (4.50 s)²
x = -2.34 m
The position of the particle is -2.34 m.
<span>Potential energy and Kinetic energy</span>
Answer:
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