A proton is fired toward a lead nucleus from very far away. How much initial kinetic energy does the proton need to reach a turn
1 answer:
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Answer : The concentration of NOBr after 95 s is, 0.013 M
Explanation :
The integrated rate law equation for second order reaction follows:
where,
k = rate constant =
t = time taken = 95 s
[A] = concentration of substance after time 't' = ?
= Initial concentration = 0.86 M
Now put all the given values in above equation, we get:
[A] = 0.013 M
Hence, the concentration of NOBr after 95 s is, 0.013 M
Answer:
Higher frequency
Explanation:
We can imagine a chemical bond between two atoms as if it were two balls connected by a spring.
According to Hooke's Law, the stretching frequency f is
where µ is the reduced mass of the system
The strength of the bond is analogous to k, the force constant of the spring. Then,
Thus, the stronger the bond, the greater the frequency of vibration.