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3 years ago

11. A 100% silver ring would be an example of a

Chemistry

2 answers:

Tomtit [17]3 years ago

5 0

Answer:

a pure substance or a compound

chubhunter [2.5K]3 years ago

3 0

Answer:

a pure substance

Explanation:

Any substance made from a single material is pure. Silver is an element just like all the others listed on the periodic table, so a block of silver is pure.

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How many formula units (f.u.'s) of GaF3 are present in 145 g of GaF3?

Ilia_Sergeevich [38]

I got D) 6.89 * 10 ^ 23

7 0

2 years ago

How much energy must be removed from a 125 g sample of benzene (molar mass= 78.11 g/mol) at 425.0 K to liquify the sample and lo

riadik2000 [5.3K]

Answer : The energy removed must be, -67.7 kJ

Solution :

The process involved in this problem are :

$(1):C_6H_6(g)(425.0K)\rightarrow C_6H_6(g)(353.0K)\\\\(2):C_6H_6(g)(353.0K)\rightarrow C_6H_6(l)(353.0K)\\\\(3):C_6H_6(l)(353.0K)\rightarrow C_6H_6(l)(335.0K)$

The expression used will be:

$\Delta H=[m\times c_{p,g}\times (T_{final}-T_{initial})]+m\times \Delta H_{vap}+[m\times c_{p,l}\times (T_{final}-T_{initial})]$

where,

$\Delta H$ = heat released by the reaction = ?

m = mass of benzene = 125 g

$c_{p,g}$ = specific heat of gaseous benzene = $1.06J/g^oC$

$c_{p,l}$ = specific heat of liquid benzene = $1.73J/g^oC$

$\Delta H_{vap}$ = enthalpy change for vaporization = $33.9kJ/mole=33900J/mole=\frac{33900J/mole}{78.11g/mole}J/g=434.0J/g$

Molar mass of benzene = 78.11 g/mole

Now put all the given values in the above expression, we get:

$\Delta H=[125g\times 1.06J/g.K\times (353.0-(425.0))K]+125g\times -434.0J/g+[125g\times 1.73J/g.K\times (335.0-353.0)K]$

$\Delta H=-67682.5J=-67.7kJ$

Therefore, the energy removed must be, -67.7 kJ

4 0

2 years ago

Anil accidentally swallows a substance that activates the complement cascade in the absence of bound antibodies. this substance

ale4655 [162]

Answer:

This substance would cause cause an extensive cellular damage to Anil.

5 0

1 year ago

Water-soluble vitamins: a. often result in toxicities b. are easily excreted in the urine c. are stored in body tissues to a lar

enyata [817]

Answer: Option (b) is the correct answer.

Explanation:

Vitamins which are soluble in water are known as water-soluble vitamins. And, vitamins which remain insoluble in water are known as water-insoluble vitamins.

Water-soluble vitamins are able to be easily excreted by the human body through urine. For example, vitamin C and vitamin B-complex are water soluble vitamins.

Thus, we can conclude that water-soluble vitamins are easily excreted in the urine.

6 0

2 years ago

B. Calculate how many atoms of hydrogen are in 1. 75 moles of glucose (c6h12o6).

ycow [4]

Answer:

1.26x10^25 atoms of hydrogen

Explanation:

because there are 12 atoms of hydrogen in a molecule of glucose, multiply 12 by Avogadro's number (6.02x10^23) to get how many molecules of hydrogen there are in a mole of glucose. Then multiply that number by 1.75, which is the number of moles of glucose there is in this problem.

4 0

2 years ago