3 years ago

How do you solve for B in 65pi=B5?

1 answer:

6 0

So assuming pi represents 1 term or the ratio of the diameter to the circumfernce and B5 means B times 5 and not B^5

65pi=B5
divide both sides by 5
(65pi)/5=B
simplify
13pi=B

You might be interested in

If (x,y) is a solution to the system of equations shown below, what is the product of the y-coordinates of the solutions? x^2+4y

aliina [53]

Answer:

The product of the y-coordinates of the solutions is equal to 3

Step-by-step explanation:

we have

$x^{2}+4y^{2}=40$ -----> equation A

$x+2y=8$ ------> equation B

Solve by graphing

Remember that the solutions of the system of equations are the intersection point both graphs

using a graphing tool

The solutions are the points (2,3) and (6,1)

see the attached figure

The y-coordinates of the solutions are 3 and 1

therefore

The product of the y-coordinates of the solutions is equal to

(3)(1)=3

4 0

3 years ago

If a movie ticket cost $10 in 2016, what was its price in 1980

zaharov [31]

Answer:

It would be in the $3.30 or lower zone

Step-by-step explanation:

8 0

4 years ago

How many petals are present when there are 12 leaves

Liono4ka [1.6K]

B. 30 petals
there is a pattern.

4 0

3 years ago

No more chocolate or transporters

Goryan [66]

Answer:

thats absolutely right

5 0

3 years ago

Read 2 more answers

A car of 1000 kg starts to move from rest and travels a distance of 150 m in 10 second. How much force is needed?

allsm [11]

Initial velocity=u=0m/s
Distance=s=150m
Time=t=10s
Acceleration=a

Using second equation of kinematics

$\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2$

$\\ \sf\longmapsto 150=0(10)+\dfrac{1}{2}a(10)^2$

$\\ \sf\longmapsto 150=\dfrac{1}{2}\times 100a$

$\\ \sf\longmapsto 50a=150$

$\\ \sf\longmapsto a=\dfrac{150}{50}$

$\\ \sf\longmapsto a=3m/s^2$

Mass=m=1000kg
Force=F

Using newtons second law

$\\ \sf\longmapsto F=ma$

$\\ \sf\longmapsto F=1000(3)$

$\\ \sf\longmapsto F=3000N$

3 0

3 years ago