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Ray Of Light [21]
3 years ago
12

8Which of the following can be found in the Kuiper Belt?

Chemistry
2 answers:
denis-greek [22]3 years ago
8 0

Answer: Pluto

Explanation:

Ganezh [65]3 years ago
5 0
The correct answer to this question is D
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Logs in a fire, and charged batteries are examples of?
vlabodo [156]

Answer:

Logs in a fire is an example of something burning, also changing its state of form. I think thats chemical change; going from wood to ashes. And charged batteries means they haven't been used yet or they were just charged, resulting in physical change.

Explanation:

I just learned this in science.

I hope this helps!

7 0
3 years ago
In which state of matter are the particles able to move around one another?
anyanavicka [17]
Particles in a:
gas are well separated with no regular arrangement.
liquid are close together with no regular arrangement.
solid are tightly packed, usually in a regular pattern.
Particles in a:
gas vibrate and move freely at high speeds.
liquid vibrate, move about, and slide past each other.
solid vibrate (jiggle) but generally do not move from place to place.
Liquids and solids are often referred to as condensed phases because the particles are very close together.
The following table summarizes properties of gases, liquids, and solids and identifies the microscopic behavior responsible for each property.
8 0
3 years ago
Porfavor necesito ayuda para solucionar esta tabla
Ivahew [28]

Explanation:

jdjddjdjei in a bit of a break and then you in Delhi for speed and your voice is so we are mad e

7 0
3 years ago
Electric power is measured in watts (1 W = 1 J/s). About 95% of the power output of an incandescent bulb is converted to heat an
nlexa [21]

Answer:

9.430 * 10¹⁷ protons per second whill shine on the book from a 62 W bulb

Explanation:

To answer this question, first let's calculate the energy of a single photon with a wavelength (λ) of 504 nm:

E = hc/λ

Where h is Planck's constant (6.626*10⁻³⁴ J·s) and c is the speed of light (3*10⁸ m/s).

E = 6.626*10⁻³⁴ J·s * 3*10⁸ m/s ÷ (504*10⁻⁹m) = 3.944 * 10⁻¹⁹ J.

So now we can make the equivalency for this problem, that

<u>1 proton =  3.944 * 10⁻¹⁹ J</u>

Now we convert watts from J/s to proton/s:

1 \frac{J}{s}*\frac{1proton}{3.944*10^{-19}J}=2.535*10^{18} \frac{proton}{s} = 1 W

Solving the problem, a 62 W bulb converts 5% of its output into light, so:

  • 62 * 5/100 = 3.1 W

3.1 watts are equal to [ 2.535*10¹⁸ proton/s * 3.1 ] = 7.858 * 10¹⁸ proton/s

Of those protons per second, 12% will shine on the chemistry textbook, thus:

7.858 * 10¹⁸ proton/s * 12/100 = 9.430 * 10¹⁷ protons/s

8 0
3 years ago
Which of the following is a unit for mass in the International System of Units?
klio [65]
Remember this King Henry Died Unfortunatly Drinking Chocolate Milk look this up online. The answer is Kilo. #TeamAlvaxic
6 0
3 years ago
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