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Mandarinka [93]
3 years ago
13

I need this all by today because I’m get 0 and my science teacher is being a

Chemistry
2 answers:
Shalnov [3]3 years ago
7 0
The cnidarias life cycle has 2 life cycles polyp and medusa
dmitriy555 [2]3 years ago
7 0

The correct answer is B their life cycle consists of two distinct phases - the polyp and medusa stage.

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several kinds of bears are found on earth. most bears are brown or black, but one type of bear, the polar bear is white. What pr
LekaFEV [45]

Explanation:

they are white so they can camouflage, but actually the polar bears skin is black and it's hair is hollow

4 0
3 years ago
Read 2 more answers
Automotive air bags inflate when sodium azide, NaN3, decomposes explosively to its constituent elements. How many moles of nitro
attashe74 [19]

Answer:

2.29 g of N2

Explanation:

We have to start with the <u>chemical reaction</u>:

NaN_3~->~Na~+~N_2

The next step is to <u>balance the reaction</u>:

2NaN_3~->~2Na~+~3N_2

We can continue with the <u>mol calculation</u> using the molar mass of

NaN_3 (65 g/mol), so:

3.55~g~NaN_3\frac{1~mol~NaN_3}{65~g~NaN_3}=0.054~mol~NaN_3

Now, with the<u> molar ratio</u> between NaN_3  and N_2  we can <u>calculate the moles</u> of N_2  (2:3), so:

0.054~mol~NaN_3\frac{3~mol~N_2}{2~mol~NaN_3}=0.0819~mol~N_2

With the molar mass of N_2 we can <u>calculate the grams</u>:

0.0819~mol~N_2=\frac{1~mol~N_2}{28~g~N_2}=2.29~g~N_2

I hope it helps!

5 0
3 years ago
Fill in the following table.
Nostrana [21]

Answer:

i cant see the photo but i would love to help

Explanation:

6 0
2 years ago
Which of the following statements correctly describe a photon? Select all that apply.
svetlana [45]

Answer:

I believe it is 3 and 4. I really hope it is but i am positive :)

6 0
3 years ago
How much mass defect is required to release 5.5 x 1020 J of energy?
Montano1993 [528]

Answer : The mass defect required to release energy is 6111.111 kg

Explanation :

To calculate the mass defect for given energy released, we use Einstein's equation:

E=\Delta mc^2

E = Energy released = 5.5\times 10^{20}J

\Delta m = mass change = ?

c = speed of light = 3\times 10^8m/s

Now put all the given values in above equation, we get:

5.5\times 10^{20}Kgm^2/s^2=\Delta m\times (3\times 10^8m/s)^2

\Delta m=6111.111kg

Therefore, the mass defect required to release energy is 6111.111 kg

5 0
3 years ago
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