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Mariulka [41]
3 years ago
6

In order for sedimentary rock to form, which of the following must occur?

Chemistry
1 answer:
Morgarella [4.7K]3 years ago
5 0

Answer:

Compaction

Explanation:

It is formed through already existing rocks so they more or less have to be compacted to form one sedimentary rock.(To oversimplify the process)

Hope this helps!!

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Which sample contains a total of 3.0 x 10^23 molecules?
belka [17]
Given that 1 mole contains 6.02x10^23 molecules, 3.0x10^23 is just around half a mole. Then we check the number of moles for each choice:

A. This is approximately half a mole, since the molar mass of Br2 is 159.8 g/mol.
B. He has a molar mass around 4 g/mol, so this is 1 mole.
C. H2 has a molar mass of 2.02 g/mol, so this is 2 moles.
D. Li has a molar mass of around 6.97 g/mol, so this is around 2 moles.

Therefore the only choice that fits is A. 80 g of Br2.
3 0
3 years ago
Label the parts of the respiratory system.
Evgesh-ka [11]

Answer:

1. Nose

2. Mouth

3. Larynx

4. Lung

5. RIght Bronchi

6. Diaphragm

7. Pharynx

8. Trachea

9. Left Bronchi

10. Bronchioles

11. Avoli

Explanation:

8 0
3 years ago
Cu + 2AgNO3 es002-1.jpg 2Ag + Cu(NO3)2 How many moles of copper must react to form 0.854 mol Ag?
marin [14]
Balance Chemical Equation is as follow,

<span>                        Cu + 2 AgNO</span>₃     →    2 Ag + Cu(NO₃)₂

According to Balance Equation,

                   2 Moles of Ag is produced by reacting  =  1 Mole of Cu
So, 
     0.854 Moles of Ag will be produced by reacting  =  X Moles of Cu

Solving for X,
                             X  =  (0.854 mol × 1 mol) ÷ 2 mol

                             X  =  0.427 Moles of Cu
Result:
            0.854 Moles of Ag 
are produced by reacting 0.427 Moles of Cu.
4 0
3 years ago
One way to limit iron corrosion is to coat the iron with a metal that:
Lorico [155]
  <span>1.)One way to limit iron corrosion is to coat the iron with a metal that: 
A.)will never undergo corrosion 

</span>
3 0
3 years ago
Read 2 more answers
Calculate the mass of ammonia (NH3) that contains a billion (1.00 * 10^12) hydrogen atoms.
Lynna [10]

Answer:

The mass of ammonia (NH3) that contains 1.00 \times 10^12 hydrogen atoms is 9.4\times 10^{-12} g.

Explanation:

As 6.022\times 10^{23} atoms of hydrogen = 1 mole of the hydrogen atom

Therefore, 10^{12} atoms of hydrogen = \frac{1}{6.022 \times 10^{23}}\times 10^{12}=1.66\times 10^{-12} moles of the hydrogen atom.

Now, there are 3 moles of hydrogen atoms in 1 mole of ammonia (NH_3).

As the mass of 1 mole of ammonia is 17g, so

when there are 3 moles of hydrogen atoms, then the mass of ammonia = 17 g

Therefore, when there are 1.66\times 10^{-12} moles of hydrogen atoms, then the mass of ammonia = \frac{17}{3}\times 1.66\times 10^{-12}=9.4\times 10^{-12 g.

Hence, the mass of ammonia (NH_3) that contains 1.00 \times 10^12 hydrogen atoms is 9.4\times 10^{-12} g.

3 0
3 years ago
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