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Vitek1552 [10]
3 years ago
7

Two airplanes leave an airport at the same time. The velocity of the first airplane is 650 m/h at a heading of 60.5 ◦ . The velo

city of the second is 560 m/h at a heading of 85◦ . How far apart are they after 2.9 h? Answer in units of m.

Physics
1 answer:
Assoli18 [71]3 years ago
7 0
First, illustrate the problem as shown in the attached picture. Next, let's find the distance traveled by planes A and B after 2.9 h.

Distance of A: 650 m/h * 2.9 h = 1,885 m
Distance of B: 560 m/h * 2.9 h = 1,624 m

Then, we use the cosine law to determine the distance x. The angle should be: 85 - 60.5 = 24.5°

x² = 1,885² + 1,624² - 2(1,885)(1,624)(cos 24.5°)
x = √619381.3183
<em>x = 787 m</em>

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8 0
3 years ago
Read 2 more answers
An electron emitted from a filament is travelling at 1.5 x 105 m/s when it enters an acceleration of an electron gun in a televi
Crank

Answer:

The acceleration of the electron is 1.457 x 10¹⁵ m/s².

Explanation:

Given;

initial velocity of the emitted electron, u = 1.5 x 10⁵ m/s

distance traveled by the electron, d = 0.01 m

final velocity of the electron, v = 5.4 x 10⁶ m/s

The acceleration of the electron is calculated as;

v² = u² + 2ad

(5.4 x 10⁶)² = (1.5 x 10⁵)² + (2 x 0.01)a

(2 x 0.01)a = (5.4 x 10⁶)² - (1.5 x 10⁵)²

(2 x 0.01)a = 2.91375 x 10¹³

a = \frac{2.91375 \ \times \ 10^{13}}{2 \ \times \ 0.01} \\\\a = 1.457 \ \times \ 10^{15} \ m/s^2

Therefore, the acceleration of the electron is 1.457 x 10¹⁵ m/s².

7 0
3 years ago
You can, in an emergency, start a manual transmission car by putting it in neutral, letting the car roll down a hill to pick up
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Answer:

The hill should be not less than 0.625 m high

Explanation:

This problem can be solved by using the principle of conservation of mechanical energy. In the absence of friction, the total mechanical energy is conserved. That means that

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When the car is in the top of the hill, its speed is 0, but its height h should be enough to produce the needed speed v down the hill.

The Kinetic energy is then, zero. When the car gets enough speed we assume it is achieved at ground level, so the potential energy runs out to zero but the Kinetic is at max. So the initial potential energy is transformed into kinetic energy.

mgh=\frac{mv^2}{2}

We can solve for h:

h=\frac{v^2}{2g}=\frac{3.5^2}{2(9.8)}=0.625m

The hill should be not less than 0.625 m high

8 0
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Answer:

force =mass *acceleration

Explanation:

force = 50*2

force =100N

8 0
3 years ago
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