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Elena-2011 [213]
3 years ago
11

Why hydrogen atom does not emit X-rays??

Physics
1 answer:
goblinko [34]3 years ago
8 0
b) it has narrow energy levels  is your answer.
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An electric hoist does 56,447 J of work in raising 115 kg load. How high (in meters) was the load lifted?
Ugo [173]

\\ \rm\rightarrowtail W=mgh

\\ \rm\rightarrowtail 56447=1150h

\\ \rm\rightarrowtail h=56447/11150

\\ \rm\rightarrowtail h=49.1m

8 0
2 years ago
PLEASE PLEASE HELP! Referring to the diagram above, predict what will happen when the switch is closed. Explain your answer.
IgorC [24]

the batteries would heat up due to the over load of power not going into any thing and the screw driver is giving it a boost of energy



8 0
3 years ago
Is work being done on a barbell when a weight lifter is holding the barbell<br> over his head?
AVprozaik [17]
I don’t see any picture sorry I wish I can help tho
7 0
2 years ago
Charlie pulls horizontally to the right on a wagon with a force of 37.2 N. Sara pulls horizontally to the left with a force of 2
Sidana [21]

Answer:

The work done on the wagon is 37 joules.

Explanation:

Given that,

The force applied by Charlie to the right, F = 37.2 N

The force applied by Sara to the left, F' = 22.4 N

We need to find the work done on the wagon after it has moved 2.50 meters to the right. The net force acting on the wagon is :

F_n=F-F'

F_n=37.2-22.4

F_n=14.8\ N

Work done on the wagon is given by the product of net force and displacement. It is given by :

W=F_n\times d

W=14.8\ N\times 2.5\ m

W = 37 Joules

So, the work done on the wagon is 37 joules. Hence, this is the required solution.

7 0
3 years ago
Read 2 more answers
2 Points
Mademuasel [1]

According to Newton's Second Law of Motion :

The Force acting on an Object is equal to Product of Mass of the Object and Acceleration produced due to the Force.

:\implies  Force acting = Mass of the Object × Acceleration

Given : Force = 50 newton and Mass of the Object = 10 kg

Substituting the respective values in the Formula, we get :

:\implies  50 N = 10 kg × Acceleration

:\implies \mathsf{Acceleration = \dfrac{50\;N}{10\;kg}}

:\implies Acceleration of the Object = 5 m/s²

4 0
3 years ago
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