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2 years ago

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A student made the claim that a 4 gram paintball fired from a paintball gun at 90 m/s could have about the same kinetic energy a

s a 1 gram BB pellet fired from a BB gun at 180 m/s.
Do you agree or disagree with the student's claim? Use evidence and mathematical reasoning to support your response.

1 answer:

vovikov84 [41]2 years ago

7 0

This question involves the concept of kinetic energy.

The student's claim is "right".

<h3>Kinetic Energy</h3>

The energy possessed by a body, by the virtue of its motion is called kinetic energy. Mathematically it is given by the following formula:

$K.E =\frac{1}{2}mv^2$

where,

K.E = Kinetic energy
m = mass
v = velocity

Therefore,

For the paintball:

$K.E = \frac{1}{2}(4\ g)(90\ m/s)^2$

K.E = 16200 J

For the pellet:

$K.E = \frac{1}{2}(1\ g)(180\ m/s)^2$

K.E = 16200 J

Hence, both paintball and pellet will have same kinetic energy. The student is right.

Learn more about kinetic energy here:

brainly.com/question/12669551

#SPJ1

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Nuclear waste disposal is one of the largest issues with nuclear power. Cesium-137 is one of the high level waste products in an

vodomira [7]

Answer:

A sample of 5.2 mg decays to .65 mg or to 1/8 of its original amount.

1/8 = 1/2 * 1/2 * 1/2 or 3 half-lives.

3 * 30.07 = 90 yrs for 5.2 mg to decay to .65 mg

You can get these other numbers similarly:

5.2 / .0102 = 510 requires about 9 half-lives which is 30 * 9 = 270 yrs

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3 years ago

A 120-V rms voltage at 1000 Hz is applied to an inductor, a 2.00-μF capacitor and a 100-Ω resistor, all in series. If the rms va

natima [27]

Answer:

The inductance of the inductor is 35.8 mH

Explanation:

Given that,

Voltage = 120-V

Frequency = 1000 Hz

Capacitor $C= 2.00\mu F$

Current = 0.680 A

We need to calculate the inductance of the inductor

Using formula of current

$I = \dfrac{V}{Z}$

$Z=\sqrt{R^2+(L\omega-\dfrac{1}{C\omega})^2}$

Put the value of Z into the formula

$I=\dfrac{V}{\sqrt{R^2+(L\omega-\dfrac{1}{C\omega})^2}}$

Put the value into the formula

$0.680=\dfrac{120}{\sqrt{(100)^2+(L\times2\pi\times1000-\dfrac{1}{2\times10^{-6}\times2\pi\times1000})^2}}$

$L=35.8\ mH$

Hence, The inductance of the inductor is 35.8 mH

4 0

3 years ago

Read 2 more answers

To get an idea of how much thermal energy is contained in the world's oceans, estimate the heat liberated when a cube of ocean w

kolbaska11 [484]

Answer:

Q = 4.52 10¹⁷ J

Explanation:

Thermal energy can be calculated with

Q = m c_{e} ΔT

in this case it indicates that we approximate seawater to pure water with

c_{e} = 4186 J/ kg K

with the density

ρ = m / V

m = ρ V

V = L³

we substitute

m = ρ L³

Q = ρ L3 c_{e} ΔT

calculate

Q = 1000 (3 103) 3 4186 4

Q = 4.52 10¹⁷ J

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3 years ago

You're using a monochromatic beam of light with wavelength 500 nm in an interferometer. What is the miminum distance you would n

Marina CMI [18]

Answer:

Minimum distance needed to move one of the mirrors = 125 nm

Explanation:

Constructive interference occurs when the maxima (trough or crest) of two waves that are in phase add together so that the amplitude of the resulting wave is equal to the sum of the individual amplitudes.

Destructive interference occurs when the maxima (trough or crest) of two waves that are out of phase by 180⁰ or half a wavelength combine to produce a smaller amplitude than the individual amplitudes that combine. It can even produce a wave of zero amplitude.

Since the spot of constructive interference has been changed to destructive interference, Path difference = Wavelength/2

Path difference = 500nm/2 = 250 nm

Path difference = 250 * 10⁻⁹ m

Since there are two interferometer's mirrors and only one is moved, the minimum distance will be a half of the path difference.

That is, minimum distance = (path difference)/2

Minimum distance = (250 * 10⁻⁹)/2

Minimum distance = 125 * 10⁻⁹ m

Minimum distance = 125 nm

5 0

3 years ago

The displacement (in meters) of a particle moving in a straight line is given by the equation of motion:

lutik1710 [3]

Answer:

At $t = 1\; \rm s$ , the particle should have a velocity of $-8\; \rm m \cdot s^{-1}$ .
At $t = 2\; \rm s$ , the particle should have a velocity of $-1\; \rm m \cdot s^{-1}$ .
At $t = 3\; \rm s$ , the particle should have a velocity of $\displaystyle -\frac{8}{27}\; \rm m \cdot s^{-1}$ .

For $a > 0$ , at $t = a \; \text{second}$ , the particle should have a velocity of $\displaystyle -\frac{8}{a^3}\; \rm m \cdot s^{-1}$ .

Explanation:

Differentiate the displacement of an object (with respect to time) to find the object's velocity.

Note that the in this question, the expression for displacement is undefined (and not differentiable) when $t$ is equal to zero. For $t > 0$ :

$\begin{aligned}v &= \frac{\rm d}{{\rm d}t}\, [s] = \frac{\rm d}{{\rm d}t}\, \left[\frac{4}{t^2}\right] \\ &= \frac{\rm d}{{\rm d}t}\, \left[4\, t^{-2}\right] = 4\, \left((-2)\, t^{-3}\right) = -8\, t^{-3} =-\frac{8}{t^3}\end{aligned}$ .

This expression can then be evaluated at $t = 1$ , $t = 2$ , and $t = 3$ to obtain the required results.

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2 years ago