Water levels tend to drop in dry weather because of evaporation. The hot temperatures will cause the water to achieve its gaseous state and go up into the atmosphere.
Using the Rydberg formula, the spectral line of H - atom is suitable for this purpose is Paschen, ∞ → 3.
- Using the Rydberg formula;
1/λ = RH(1/nf^2 - 1/ni^2)
Given that;
λ = wavelength
RH = Rydberg constant
nf = final state
ni = initial state
- When final state = 3 and initial state = ∞
Then;
1/λ = 1 × 10^7 m-1 (1/3^2 - 1/ ∞^2)
1/λ = 1 × 10^7 m-1 (1/3^2 )
λ = 900 nm
Hence, the correct answer is Paschen, ∞ → 3
Learn more about the Rydberg formula; brainly.com/question/17753747
Answer:
c = 0.377 J/g.°C
c = 0.2350 J/g.°C
J = 27.3 J
Explanation:
We can calculate the heat (Q) absorbed or released by a substance using the following expression.
Q = c × m × ΔT
where,
c: specific heat
m: mass
ΔT: change in the temperature
<em>It takes 49.0J to raise the temperature of an 11.5g piece of unknown metal from 13.0°C to 24.3°C. What is the specific heat for the metal? Express your answer numerically, in J/g.°C</em>
Q = c × m × ΔT
49.0 J = c × 11.5 g × (24.3°C - 13.0°C)
c = 0.377 J/g.°C
<em>The molar heat capacity of silver is 25.35 J/mol.°C. How much energy would it take to raise the temperature of 11.5g of silver by 10.1°C? Express your answer numerically, in Joules. What is the specific heat of silver?</em>
<em />
The molar mass of silver is 107.87 g/mol. The specific heat of silver is:

Q = c × m × ΔT
Q = (0.2350 J/g.°C) × 11.5 g × 10.1°C = 27.3 J
It’s the greenhouse effect. Hope this helps!
Answer:
C₁₂H₂₂O₁₁ (C₁₂H₂₂O₁₁ ).
Explanation:
The empirical formula is obtained when we divide the molecular formula with a whole number giving the simplest ratio of all the elements (in whole number).
a) C₁₂H₂₂O₁₁ :
There is no number with which we can divide the ratio further to get a simpler formula hence the molecular formula of the given compound is the empirical formula of the compound. Hence it is correct.
(C₁₂H₂₂O₁₁),
(b) C₈H₁₂O₄
The empirical formula can be obtained by dividing the formula with "4"
The empirical formula would be
(C₂H₃O)
(c) H₂O₂
The empirical formula would be (H₁O₁)